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Marina86 [1]
3 years ago
13

Consider two less-than-desirable options.

Physics
1 answer:
Gemiola [76]3 years ago
7 0

Answer:

The force would be the same in both cases - option C.

Explanation:

The change in momentum is known as an impulse. In the two cases under consideration, the change in momentum is the same, thus impulse for both cases is the same.

Impulse is the average force multiplied by time interval.

I = F(average)*ΔT. Where F(average) is the average force and ΔT is the time interval.

The average force in both cases is the same since the collision time is the same.

Thus option C is the correct answer.

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While running, a person dissipates about 0.60 J of mechanical energy per step per kilogram of body mass. If a 61 kg person devel
liraira [26]

Answer:

2.66m/s

Explanation:

information we have

power: 65W

work per step per kilogram: 0.60J

mass: 61kg

length of a running step: 1.5m

---------------

the formula for power is:

P=\frac{W}{t}

where W is the work and t is time.

time is also defined as: t=\frac{distance}{velocity}=\frac{d}{v}

so substituting this into the formula for power we get:

P=\frac{W*v}{d}

where v is the velocity we are looking for, d is the distance per step: d=1.5m, W is the work per step and P is power P=65W.

we know that the work per step per kilogram is:

0.60J

so to find the work per step of his whole body we need to multiply the 0.60J by the 61 kilograms of his mas:

W=0.60J*61kg\\W=36.6Jthis is the work per step of the person.

So now we can calculate the velocity using the formula for power

P=\frac{W*v}{d}

clearing for v:

v=\frac{P*d}{W}\\

and substituting known values:

v=\frac{(65W)(1.5m)}{36.6J}= 2.66m/s

6 0
3 years ago
What happens to the change in the value of the speed as you increased the amount of force applied on your
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Answer:

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Explanation:

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Difference between output work and input work​
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An input device sends information to a computer system for processing, and an output device reproduces or displays the results of that processing. Input devices only allow for input of data to a computer and output devices only receive the output of data from another device.

Hope it helps!

8 0
3 years ago
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