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Arada [10]
3 years ago
13

2 Grade 11 Physics Questions. Will Mark BRAINLIEST!!!

Physics
2 answers:
Stels [109]3 years ago
7 0

Answer:

For the first one it would be screw and for the second one it is a ramp

Explanation:

Hope this helps

Viktor [21]3 years ago
3 0
Thanks for the help
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A gold nucleus is 466 fm (1 fm = 10-15 m) from a proton, which initially is at rest. When the proton is released, it speeds away
Artist 52 [7]

Answer:

v=6.8\times10^6m/s

Explanation:

The sum of the kinetic and electric potential energies of the proton when initially released must be equal to their sum at infinity, so we have:

K_i+U_i=K_f+U_f

Which, since K_i=0J because initially the proton is at rest, is:

\frac{kqQ}{d}=\frac{mv^2}{2}+\frac{kqQ}{r_\infty}

where k=9\times10^9Nm^2/C^2 is Coulomb's constant, q=1.6\times10^{-19}C the charge of the proton, Q=(79)(1.6\times10^{-19})C the charge of the gold nucleus, since it has 79 protons, d=466\times10^{-15}m the initial separation between them, m=1.67\times10^{-27}kg the mass of the proton and v its final velocity. r_\infty is very far away, so the final electric potential will be 0J, and we have:

v=\sqrt{\frac{2kqQ}{md}}=\sqrt{\frac{2(9\times10^9)(1.6\times10^{-19})^2(79)}{(1.67\times10^{-27})(466\times10^{-15})}}m/s=6839409m/s

8 0
3 years ago
Which takes more energy, going from 0 to 30, or from 30 to 60?
AfilCa [17]
0 to 30 takes more energy
3 0
3 years ago
The _____ period refers to the first two weeks of development after conception.
Mrac [35]

Answer: Geminal

Explanation:

5 0
3 years ago
Read 2 more answers
What is the answer to this​
umka2103 [35]
It’s the atomic mass
3 0
3 years ago
A girl moves quickly to the center of a spinning merry-go-round, traveling along the radius of the merry-go-round. Which of the
DochEvi [55]

Answer:

The angular speed of the system increases.

The moment of inertia of the system decreases.

Explanation:

As we know that the girl is going towards the center of the circle so here the moment of inertia of the girl is given as

I = mr^2

here we know that

r = position of the girl from the center of the disc

now we know that the girl is moving towards the center so its distance will continuously decreasing

So the moment of inertia of the girl will decrease

Now we know that that with respect to the center of the disc there is no torque on the disc + girl system

So here we can use angular momentum conservation

So we have

I\omega = constant

since moment of inertia is decreasing for the system

so angular speed will increase

3 0
4 years ago
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