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Vesnalui [34]
2 years ago
5

What condition did the new jersey representatives include in the resolution for a nuclear freeze?

Physics
1 answer:
vovangra [49]2 years ago
6 0

The condition new jersey representatives include in the resolution for a nuclear freeze is verifiable.

The nuclear freeze was a campaign for mass resolution in the United States during the late 1980's to secure an argument between the U.S and Soviet arguments to halt the testing, production, and deployment of nuclear weapons.

Halting an atomic weapon is theoretically possible, but in reality, it is an enormous challenge. The Russian invasion of Ukraine has raised the fear of of nuclear weapons to a level not seen since the Cold War.

Thus, the main challenge is now rising that how can one protect themselves from nuclear radiation after a war.

To learn more about Nuclear Freeze, here

brainly.com/question/1890464

#SPJ4

You might be interested in
Can an atom exist without a nucleus
Stolb23 [73]
No. Atom cannot exist without a nucleus. There would be only one part in an atom if nucleus would be deleted and that will be "Electrons", when electrons will be alone they will be just electron not an atom. 

In short, Atom can't exist without a nucleus

Hope this helps!
7 0
3 years ago
Whu is it important to mave regular supervision of weights and measurements in the market​
pentagon [3]

Answer:

Hope the answer helped you. if yes pls follow me

Explanation:

the fundamental answer is without regular supervision of definition of weights and measures,commerce exchange will be impossible and there would be no market whatsoever for anything.

5 0
3 years ago
A liquid with a density of 900kg/m 3 is stored in a pressurized, closed storage tank. The tank is cylindrical with a 10m diamete
Orlov [11]

Answer:

18.62 m/s

Explanation:

Given that:

A liquid with a density of 900 kg/m 3 is stored in a pressurized, closed storage tank.

Diameter of the tank = 10 m

The absolute pressure in the tank above the liquid is 200 kPa = 200, 000 Pa

At pressure of 200 kPa   ; the final velocity = 0

Atmospheric pressure at 5cm = 101325 Pa

We are to calculate the initial velocity of a fluid jet when a 5cm diameter orifice is opened at point A?

By using Bernoulli's theorem between the shaded portion in the diagram;

we have:

Pa \ + \ \frac{1}{2} \  \delta \ v^2_1 \ + \ \delta gy_1 = P + \delta gy_2

\frac{1}{2} \  \delta \ v^2_1 \ = P + \delta gy_2 -  \ \delta gy_1  - Pa

\frac{1}{2} \  \delta \ v^2_1 \ =  \delta g(y_2 -y_1 )+   ( P   - Pa )

v_1 \ =  \sqrt{ \frac {2 \ \delta g(y_2 -y_1 )+  2  ( P   - Pa )}{\delta}}

where;

Pa = atmospheric pressure = 101325 Pa

\delta = density of liquid = 900 kg/m³

v_1 = initial velocity = ???

g = 9.8 m/s²

y_1 = height of the hole from the buttom

y_2 = height of the liquid surface from the button

v_1 \ =  \sqrt{ \frac {2*900*9.8(7 -  0.5 )+  2  ( 200,000   - 101325 )}{900}}

v_1 = 18.62 \ m/s

Thus, the initial  velocity of the fluid jet  = 18.62 m/s

3 0
3 years ago
Which tool would be most useful to identify areas with frequent earthquakes to predict future earthquakes?
enyata [817]
It is a seismograph that would be most useful.
6 0
3 years ago
If a stress of 1.05 × 107 n/m2 is applied to his ligament, how much will it stretch? the young\'s modulus for the acl is 1.10 ×
Ainat [17]

As we know that

Young's\: Modulus = \frac{stress}{strain}

here we know that

Young's Modulus = 1.10 \times 10^8

stress = 1.05 \times 10^7

now by the above formula we will have

1.10 \times 10^8 = \frac{1.05 \times 10^7}{strain}

strain = \frac{1.05 \times 10^7}{1.10 \times 10^8}

strain = 0.095


3 0
3 years ago
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