Question

If a stress of 1.05 × 107 n/m2 is applied to his ligament, how much will it stretch? the young\'s modulus for the acl is 1.10 × 108 n/m2.

Answer 1

As we know that

$Young's\: Modulus = \frac{stress}{strain}$

here we know that

$Young's Modulus = 1.10 \times 10^8$

$stress = 1.05 \times 10^7$

now by the above formula we will have

$1.10 \times 10^8 = \frac{1.05 \times 10^7}{strain}$

$strain = \frac{1.05 \times 10^7}{1.10 \times 10^8}$

$strain = 0.095$