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Pavlova-9 [17]
1 year ago
11

A composite plane wall consists of a 5-in.-thick layer of insulation (ks = 0.029 Btu/h*ft*°R) and a 0.75-in.-thick layer of sidi

ng (ks = 0.058 Btu/h*ft*°R). The inner temperature of the insulation is 67°F. The outer temperature of the siding is -8°F.
Determine at steady state:


(a) the temperature at the interface of the two layers, in °F, and (b) the rate of heat transfer through the wall in Btu/h*ft^2 of surface area.
Engineering
1 answer:
Leno4ka [110]1 year ago
3 0

We have that  the <em>temperature </em>at the <em>interface </em>of the two <em>layers</em>, in °F, and (b) the rate of heat transfer through the wall in Btu/h*ft^2 of surface area is given as

a)    T_i-12.11^oF

b) H_r=3.80 btu/hft^2\\\\

From the question we are told

A composite plane wall cons<em>i</em>sts of a 5-in.-thick layer of insulation (ks = 0.029 Btu/h*ft*°R) and a 0.75-in.-thick layer of siding (ks = 0.058 Btu/h*ft*°R).

The inner temperature of the insulation is 67°F. The outer temperature of the siding is -8°F.

<h3>Interface Temperature</h3>

Generally the equation for the Terminal resistance   is mathematically given as

R_1=\frac{t_1}{k_1A}\\\\R_1=14.3667hft^2R/btu\\\\Also\\\\R_2=\frac{t_2}{k_2A}\\\\R_2=1.077hft^2R/btu\\\\

b)

Heat transfer rate\\\\H_r=\frac{67-8}{15.444}\\\\H_r=3.80 btu/hft^2\\\\

a)Interface Temp(T_i)

T_i=\frac{67-t_2}{R1}=3.820

For more information on Temperature visit

brainly.com/question/15267055

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Answer:

A)

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B )

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attached below is a detailed solution

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B ) calculate  - Q ( KJ )

- Q ( kj ) for vapor  = -1258.05 kJ

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