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gtnhenbr [62]
3 years ago
9

Any three difference between distance and displacement​

Physics
1 answer:
nataly862011 [7]3 years ago
7 0

Answer:

1.) distance is always positive while displacement can be negative as well.

2.) distance cannot be 0 but displacement can be 0.

3.) distance is a scalar quantity while displacement is vector quantity.

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Seeing a police officer ahead and not being sure of the speed limit, a driver slows from 65 mi/hr to 55 mi/hr in 4.0 seconds, tr
Flauer [41]

Answer:

-1.13 m/s^2

Explanation:

The acceleration of the car is given by:

a=\frac{v-u}{t}

where

v is the  final velocity

u is the initial velocity

t is the time

Here we have to convert the velocities from mi/hr to m/s. Keeping in mind that

1 mi = 1609 m

1 h = 3600 s

We get:

u = 65 mi/h \cdot \frac{1609}{3600}=29.1 m/s\\v = 55 mi/h \cdot \frac{1609}{3600}=24.6 m/s

While the time interval is

t = 4.0 s

Substituting,

a=\frac{24.6 - 29.1}{4.0}=-1.13 m/s^2

3 0
3 years ago
A new system of units is invented where the basic unit of length is the "dak." The "dak" is defined as equal to 3 inches, and th
Goryan [66]

Answer:

1 cm = 0.131 daks

Explanation:

It is given that,

1 dak = 3 inches

and

1 inch = 2.54 cm

We need to find how many "daks" are there in a centimeter. We can do the conversions as follows :

1\ dak=1\ dak\times \dfrac{3\ inches}{1\ dak}\times \dfrac{2.54\ cm}{1\ inch}

1\ dak=7.62\ cm

1\ cm=\dfrac{1}{7.62}\ dak

1 cm = 0.131 dak

So, there are 0.131 daks in 1 centimeter. Hence, this is the required solution.

5 0
3 years ago
Explain Resistor in parallel and series. ​
patriot [66]

\sf\huge\underline\blue{Resistor:-}

\rightarrow<u>A resistor is a passive two-terminal electrical component that implements electrical resistance as a circuit element</u>.

\rightarrowResistors reduce the current flow and lower voltage levels within circuits.

\sf\large\underline\purple{Resistors \:in\: Series:-}

\rightarrowA <u>circuit is said to be connected in series</u> when the same amount of <u>current flows through the resistors</u>. In such circuits, the voltage across each resistor is different.

\rightarrowIn a series connection, if any resistor is broken or a fault occurs, then the entire circuit is turned off. The construction of a series circuit is simpler compared to a parallel circuit.

\rightarrowFor the above circuit(attached image-1), the total resistance is given as:

\sf{R_{total}\: = \:R1 + R2 + ….. + Rn}

The total resistance of the system is just the total of individual resistances.

\sf\large\underline\purple{Resistors \:in\: Parallel:-}

\rightarrowA <u>circuit is said to be connected in parallel</u> when the <u>voltage is the same across the resistors</u>. In such circuits, the current is branched out and recombines when branches meet at a common point.

\rightarrowA resistor or any other component can be connected or disconnected easily without affecting other elements in a parallel circuit.

\rightarrowThe figure(attached image -2) above shows ‘n’ number of resistors connected in parallel. The following relation gives the total resistance here

\sf{\frac{1}{R_{total}}\: = \:\frac{1}{R1} + \frac{1}{R2} + ….. + \frac{1}{Rn}}

\rightarrowThe sum of reciprocals of resistance of an individual resistor is the total reciprocal resistance of the system.

_______________________________

Hope it helps you:)

6 0
2 years ago
Read 2 more answers
For a process at constant pressure, 12,400 calories of heat are released. this quantity of heat is equivalent to
Vinvika [58]

Answer:

51,882 J

Explanation:

In order to convert the heat from calories to joule, we must remember the conversion factor:

1 cal = 4.184 J

Keeping in mind this, we can set up a proportion to find how much Joules correspond to 12,400 calories:

1 cal : 4.184 J = 12,400 cal : x\\x=\frac{(4.184 J)(12400 cal)}{1 cal}=51,882 J

6 0
3 years ago
A bus initially moving at 20 m/s with an acceleration of -4m/s² for 5
Alborosie

Answer:

50m; 0m/s.

Explanation:

Given the following data;

Initial velocity = 20m/s

Acceleration, a = - 4m/s²

Time, t = 5secs

To find the displacement, we would use the second equation of motion;

S = ut + \frac {1}{2}at^{2}

Substituting into the equation, we have;

S =20*5 + \frac{1}{2}*(-4)*5^{2}

S =100 + (-2)*25

S =100 - 50

S = 50m

Next, to find the final velocity, we would use the third equation of motion;

V^{2} = U^{2} + 2aS

Where;

  • V represents the final velocity measured in meter per seconds.
  • U represents the initial velocity measured in meter per seconds.
  • a represents acceleration measured in meters per seconds square.

<em>Substituting into the equation, we have;</em>

V^{2} = 20^{2} + 2(-4)*50

V^{2} = 400 - 400

V^{2} = 0

V = 0m/s

<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>

5 0
3 years ago
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