What force is affected when the distance between two objects remains the same and the mass of each object is doubled?.
1 answer:
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Answer:
15.106 N
Explanation:
From the given information,
The weight of the bucket can be calculated as:
The mass of the water accumulated in the bucket after 3.20s is:
To determine the weight of the water accumulated in the bucket, we have:
For the speed of the water before hitting the bucket; we have:
v = 8.4 m/s
Now, the force required to stop the water later when it already hit the bucket is:
F = 1.68 N
Finally, the reading scale is:
= 7.154 N + 6.272 N + 1.68 N
= 15.106 N
The final velocity of the skater is 2.34 m/s forward
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system before and after the ball is thrown must be conserved, in absence of external forces.
Before the ball is thrown, the total momentum is:
where
M = 61 kg is the mass of the skater
m = 4.0 kg is the mass of the ball
u = 2.5 m/s (forward) is the combined velocity of the skater and the ball
After, the ball is thrown at twice the velocity, so the final total momentum is
where
V is the final velocity of the skater
v = 2(2.5) = 5.0 is the final velocity of the ball
Since the total momentum must be conserved, we can write
So, the skater is moving at 2.34 m/s (forward) after the shot.
Learn more about momentum:
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