The force exerted on the box is 56 N
Explanation:
The work done by a force on an object is given by

where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
For the box in this problem, we have:
W = 2240 J is the work done
d = 40 m is the displacement of the box
Assuming that the force is parallel to the displacement, 
Solving the equation for F, we find the force exerted on the box:

Learn more about work:
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It might be c I'm not sure either. Hope I helped
Answer:
f = 5 cm
Explanation:
using the thin lens equation, given as follows:

where,
f = focal length = ?
do = the distance of object from lens = 20 cm
di = the distance of image from lens = 6.6667 cm
Therefore,

<u>f = 5 cm</u>
Answer:
D
Explanation:
The reproduction parts of the plant are in the flower and around it so this would eliminate the plants ablity to reproduce.
Answer:
15.2 s
Explanation:
Convert hp to W:
55.0 hp × 746 W/hp = 41,030 W
Power = energy / time
41030 W = 6.22×10⁵ J / t
t = 15.2 s