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ella [17]
2 years ago
9

Which member of each pair is more soluble in diethyl ether? Why? (a) NaCl(s) or HCl(g)

Chemistry
1 answer:
Ede4ka [16]2 years ago
7 0

HCl is more soluble in diethyl ether.

<h3>Reason ; </h3>

H-Cl is a covalent molecule with a dipole-dipole interaction. As a result, diethyl ether may easily replace HCl's dipole-dipole interaction to dissolve it. As a result, HCl dissolves more easily in diethyl ether than NaCl. As a result, HCl(g) dissolves more easily in diethyl ether than NaCl (s).

<h3>What is Covalent molecule ?</h3>

A covalent bond is a chemical relationship that requires the sharing of electrons between atoms to generate electron pairs. These electron pairs are known as shared pairs or bonding pairs, and covalent bonding is the stable equilibrium of attractive and repulsive forces between atoms when they share electrons.

<h3>What is dipole-dipole interaction ?</h3>

Dipole-dipole interactions are weak interactions that occur when permanent or induced dipoles come into close proximity. These forces are referred to collectively as Van der Waals interactions. Proteins have a vast number of these interactions, the strength of which varies greatly.

To know more about Covalent bond please click here ; brainly.com/question/3447218

#SPJ4

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First find the mass

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the equation

Ca + O2 → CaO

= 55 grams of O2


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The consentration of a solution can be changed by _____ solute
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How many grams of zinc metal will react completely with 7.8 liters of 1.6 M HCl? Show all of the work needed to solve this probl
Andru [333]

<u>Answer:</u>

For 1: The correct answer is 407.97 grams.

For 2: The correct answer is 76.72 grams.

<u>Explanation:</u>

  • <u>For 1:</u>

We are given the molarity of HCl, to find the moles of HCl, we use the formula:

Molarity=\frac{\text{Moles}{\text{Volume}}

We are given:

Molarity = 1.6 M

Volume = 7.8 L

Putting values in above equation, we get:

1.6mol/L=\frac{\text{Moles of HCl}}{7.8L}\\\\\text{Moles of HCl}=12.48mol

For the given reaction:

Zn(s)+2HCl(aq.)\rightarrow ZnCl_2(aq.)+H_2(g)

By Stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of zinc metal.

So, 12.48 moles of HCl react with = \frac{1}{2}\times 12.48=6.24mol of Zinc metal.

To calculate the mass of zinc metal, we use the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    .....(1)

Molar mass of Zinc metal = 65.38 g/mol

6.24=\frac{\text{Mass of zinc metal}}{65.38g/mol}\\\\\text{Mass of zinc metal}=407.97g

  • <u>For 2:</u>

We are given that 298 grams of 83.1 % by mass of iron (II) nitrate solution are present.

So, mass of Iron (II) nitrate solution will be = \frac{83.1}{100}\times 298=247.638g

Molar mass Iron (II) nitrate = 180 g/mol

Putting values in equation 1, we get:

\text{Moles of }Fe(NO_3)_2=\frac{247.638g}{180g/mol}=1.37mol

For the following reaction:

2Al(s)+3Fe(NO_3)_2(aq.)\rightarrow 3Fe(s)+2Al(NO_3)_3(aq.)

By Stoichiometry of the reaction:

3 moles of Fe(NO_3)_2 produces 3 moles of iron metal.

So, 1.37 moles of Fe(NO_3)_2 will produce = \frac{3}{3}\times 1.37=1.37mol of iron metal.

To calculate the mass of zinc metal, we equation 1:

1.37=\frac{\text{Mass of iron metal}}{56g/mol}\\\\\text{Mass of iron metal}=76.72g

5 0
2 years ago
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