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ella [17]
2 years ago
9

Which member of each pair is more soluble in diethyl ether? Why? (a) NaCl(s) or HCl(g)

Chemistry
1 answer:
Ede4ka [16]2 years ago
7 0

HCl is more soluble in diethyl ether.

<h3>Reason ; </h3>

H-Cl is a covalent molecule with a dipole-dipole interaction. As a result, diethyl ether may easily replace HCl's dipole-dipole interaction to dissolve it. As a result, HCl dissolves more easily in diethyl ether than NaCl. As a result, HCl(g) dissolves more easily in diethyl ether than NaCl (s).

<h3>What is Covalent molecule ?</h3>

A covalent bond is a chemical relationship that requires the sharing of electrons between atoms to generate electron pairs. These electron pairs are known as shared pairs or bonding pairs, and covalent bonding is the stable equilibrium of attractive and repulsive forces between atoms when they share electrons.

<h3>What is dipole-dipole interaction ?</h3>

Dipole-dipole interactions are weak interactions that occur when permanent or induced dipoles come into close proximity. These forces are referred to collectively as Van der Waals interactions. Proteins have a vast number of these interactions, the strength of which varies greatly.

To know more about Covalent bond please click here ; brainly.com/question/3447218

#SPJ4

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Number the elements sodium, magnesium, and potassium in the predicted order of ionic radius from the largest (1) to the smallest
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Potassium ,sodium, and magnesium
7 0
3 years ago
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A disk of radius 2.0 cm has a surface charge density of 6.3 μC/m2 on its upper face. What is the magnitude of the electric field
maksim [4K]

Answer:

the electric field at Z = 12 cm is E =   9.68 × 10³ N/C = 9.68 kN/C

Explanation:

Given: radius of disk, R = 2.0 cm = 2 × 10⁻² cm, surface charge density,σ = 6.3 μC/m² = 6.3 × 10⁻⁶ C/m², distance on central axis, z = 12 cm = 12 × 10⁻² cm.

The electric field, E at a point on the central axis of a charged disk is given by E = σ/ε₀(1 - \frac{z}{\sqrt{z^{2} + R^{2} }  })

Substituting the values into the equation, it becomes

E = σ/ε₀(1 - \frac{z}{\sqrt{z^{2} + R^{2} }  }) = 6.3 × 10⁻⁶/8.854 × 10⁻¹²(1 - \frac{0.12}{\sqrt{0.12^{2} + 0.02^{2} } }) = 7.12 × 10⁵(1 - \frac{0.12}{0.1216}) = 7.12 × 10⁵(1 - 0.9864) = 7.12 × 10⁵ × 0.0136 = 0.0968 × 10⁵ = 9.68 × 10³ N/C = 9.68 kN/C

Therefore, the electric field at Z = 12 cm is E =   9.68 × 10³ N/C = 9.68 kN/C

7 0
3 years ago
3.2 moles of H3PO4 to grams
Nimfa-mama [501]

Answer:

313, 6grams of H3PO4

Explanation:

We calculate the weight of 1 mol of H3PO4:

Weight 1 mol H3PO4= (Weight H)x3+ (Weight P)+(Weight 0)x4  =1gx3+31g+16gx4

Weight 1 mol H3PO4=98 g /mol

1 mol-----98 grams H3PO4

3,2mol----x= (3,2molx 98 grams H3PO4)/ 1mol=313,6 grams H3PO4

4 0
3 years ago
How many chlorine ions are required to bond with one aluminum ion and why??
antiseptic1488 [7]
3 Chlorine ions are required to bond with one aluminum ion.

In ionic bonds, metals atoms loses all its outermost shell electrons to form a cation. While, non metal atoms gains however many electrons in order to make its outermost electron shell be 8 (or 2 if there's only one shell).

Therefore, form the periodic table, we can see that aluminum has a atomic number of 13, which makes its electron arrangement be 2,8,3. So, in order to form a aluminum ion, an Al atom must lose 3 electrons. On the other hand, Chlorine has a atomic number of 17, which means it has the electron configuration of 2,8,7. It has to gain only 1 electron to have 8 outermost shell electron.

Thereofre, 3 Chlorine atom are required to gain all 3 electrons given out by just 1 aluminum ion.
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Brainllest! Why are they called hot air balloons and not cold air balloons? Be sure to use the terms density, volume, and mass i
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Hot air balloons have hot air inside them, which is less dense as the air around it. Thus it rises. A cold air balloon would sink because the air would be more dense than the air around it. Also, the balloon’s volume would vary in size depending on the weight of the balloon.
7 0
3 years ago
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