Answer:
9.80 g
Explanation:
The molecular mass of the atoms mentioned in the question is as follows -
S = 32 g / mol
F = 19 g / mol
The molecular mass of the compound , SF₆ = 32 + ( 6 * 19 ) = 146 g / mol
The mass of 6 F = 6 * 19 = 114 g /mol .
The percentage of F in the compound =
mass of 6 F / total mass of the compound * 100
Hence ,
The percentage of F in the compound = 114 g /mol / 146 g / mol * 100
78.08 %
Hence , from the question ,
In 12.56 g of the compound ,
The grams of F = 0.7808 * 12.56 = 9.80 g
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N₂, H₂, NH₃ are present in the reaction mixture when equilibrium has been obtained.
Balanced chemical reaction: 3H₂ + N₂ ⇄ 2NH₃
Hydrogen (H₂ ) and nitrogen (N₂) are reactants.
Ammonia (NH₃) is product of the reaction.
Reaction goes in both direction, both reactants and product are present.
The amount of substance of reactants and products of reaction do not change when chemical reaction is in chemical equilibrium.
In a chemical reaction, chemical equilibrium is the state in which both reactants and products are present in concentrations which not change with time.
Speed of direct and irreversible chemical reaction are equal.
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