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blagie [28]
2 years ago
5

The instructions for the experiment direct you to prepare 30 mL of 1.5 M HCl solution. In the chemical closet, you locate an 18M

stock solution of HCl. What volume of the 18M HCl is needed to make the solution?
Chemistry
1 answer:
MAVERICK [17]2 years ago
6 0

The volume of the 18M HCl needed to make the solution will be 2.5 mL.

<h3>Dilution</h3>

According to the dilution principle, the number of moles of solutes in a solution before and after dilution must remain the same.

Since, mole = molarity x volume

Thus, molarity x volume before dilution = molarity x volume after dilution.

Mathematically, the equation is written as: m1v1 = m2v2

In this case, m1 = 18 M, m2 = 1.5 M, and v2 = 30 mL.

What we are looking for is v1, the amount of the stock HCl needed for dilution.

v1 = m2v2/m1 = 1.5 x 30/18 = 2.5 mL.

Thus, 2.5 mL of the stock HCl would be needed.

More on dilution can be found here: brainly.com/question/21323871

#SPJ1

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Answer:

8.45 M

Explanation:

To solve this problem we need to keep in mind the <em>definition of molarity</em>:

  • Molarity = moles / volume

First we<u> calculate the moles of AlCl₃ </u>in 0.672 L of a 4.78 M solution:

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Then we <u>calculate the new molarity of the AlCl₃ solution</u> using that <em>number of moles, which remains the same throughout the evaporation process</em>:

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What is the [H+] of a solution with a pH of 9.40?
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Answer:

a) 3.98 x 10^-10

Explanation:

Hello,

In this case, for the given pH, we can compute the concentration of hydronium by using the following formula:

pH=-log([H^+])

Hence, solving for the concentration of hydronium:

[H^+]=10^{-pH}=10^{-9.40}\\

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