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blagie [28]
2 years ago
5

The instructions for the experiment direct you to prepare 30 mL of 1.5 M HCl solution. In the chemical closet, you locate an 18M

stock solution of HCl. What volume of the 18M HCl is needed to make the solution?
Chemistry
1 answer:
MAVERICK [17]2 years ago
6 0

The volume of the 18M HCl needed to make the solution will be 2.5 mL.

<h3>Dilution</h3>

According to the dilution principle, the number of moles of solutes in a solution before and after dilution must remain the same.

Since, mole = molarity x volume

Thus, molarity x volume before dilution = molarity x volume after dilution.

Mathematically, the equation is written as: m1v1 = m2v2

In this case, m1 = 18 M, m2 = 1.5 M, and v2 = 30 mL.

What we are looking for is v1, the amount of the stock HCl needed for dilution.

v1 = m2v2/m1 = 1.5 x 30/18 = 2.5 mL.

Thus, 2.5 mL of the stock HCl would be needed.

More on dilution can be found here: brainly.com/question/21323871

#SPJ1

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The poisonous gas hydrogen sulfide, H2S, can be neutralized with a base such as sodium hydroxide,
mariarad [96]

Answer:

It's not correct. For balancing, we need to put the coefficients in the molecule, not in the athom. Because if you do this, you're creating another molecule, instead of a balacing, for which the reaction may not happen - but anyway, it would be another reaction.

The correct balacing is:

2NaOH + 1H2S → 1Na2S + 2H2O

Explanation:

Look: Na2OH does not even exist. OH has only one free link, so he can't - in normal conditions - make another one with any athom. That's why we should write 2NaOH instead of Na2OH. The first means "2 mols of NaOH".

4 0
3 years ago
A substance is analyzed and found to contain 85.7% carbon and 14.3% hydrogen by weight. A gaseous sample of the substance is fou
atroni [7]

Answer:

The empirical formula of the compound is CH2

Explanation:

<u>Step 1:</u> Data given

A substance contains 85.7 % carbon and 14.3 % hydrogen.

The substance has a density of 1.87 g/L

1 mol occupies 22.4 L

Molar mass of carbon = 12 g/mol

Molar mass of hydrogen = 1.01 g/mol

<u>Step 2</u>: Calculate molar mass of the substance

Since 1 mol occupies 22.4 L;

1 mol of this substance = 1.87g/L *22.4 = 41.888 grams

This means the molar mass of the substance is 41.888 g/mol

<u>Step 3:</u> Calculate mass of carbon:

85.8 % is carbon

this means 41.888 * 0.858 = 35.94 grams

<u>Step 4: </u>Calculate moles of carbon

moles C = mass C/ Molar mass C

Moles C = 35.94 grams / 12 g/mol

Moles C = 2.995 moles

<u>Step 5:</u> Calculate mass of hydrogen:

14.3 % is hydrogen

this means 41.888 * 0.143 = 5.99 grams

<u>Step 6 :</u>Calculate moles of hydrogen

Moles H  = 5.99 grams / 1.01 g/mol

Moles H = 5.93 moles

<u>Step 7: </u>Calculate  mol ratio

Ratio C:H = 1:2

The empirical formule = CH2

<u>Step 8</u>: calculate molar formule

Molar mass of empirical formule = 14.02 g/mol

n = Molar mass of substance / molar mass of empirical formule

n = 41.888 / 14.02 = 3

This means we have to multiply the empirical formula by 3

3*(CH2) = C3H6

C3H6 can be propene or cyclopropane

5 0
3 years ago
For each reaction below, use the drop-down menus to select which compound will form a precipitate. Note: It is possible that no
Dimas [21]

Answer:

1. Cadmium sulfide

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8 0
2 years ago
Calculate the delta S rxn at 25 degrees celsius for the reaction 2NH3(g)-&gt;&gt;N2H4(g) + H2(g). Do you know where I can find t
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In order to find your answer you need to be <span>measuring entropy, so you will be using the following formula:
</span><span>delta S= S of (N2H4) + S of ( H2) - [2( S of NH3)]
</span>Hope this is very useful for you
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3 years ago
What takes longer to melt a small quantity or a large quantity?
My name is Ann [436]

Answer:

A large quantity

Explanation:

A large quantity will take much longer to melt compared to a small quantity of the same matter.

The rate of melt of a substance is particularly a function of the nature of the substance and the amount of energy supplied to it.

If we assume that we are dealing with different quantities of the same substance, then the one that has more mass will melt faster because less energy would be required to change its state.

A large quantity of matter will take more time to melt.

7 0
3 years ago
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