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3 years ago

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You have 0.672 L of 4.78 M aqueous AlCl3 solution in a glass. If you gently heat the solution until only 0.380 L is left, what i

s the new molarity of the AlCl3 solution?

1 answer:

vlada-n [284]3 years ago

3 0

Answer:

8.45 M

Explanation:

To solve this problem we need to keep in mind the <em>definition of molarity</em>:

Molarity = moles / volume

First we<u> calculate the moles of AlCl₃ </u>in 0.672 L of a 4.78 M solution:

Moles = Molarity * volume

Moles = 4.78 M * 0.672 L

Moles = 3.212 moles

Then we <u>calculate the new molarity of the AlCl₃ solution</u> using that <em>number of moles, which remains the same throughout the evaporation process</em>:

New Molarity = 3.212 moles / 0.380 L

New Molarity = 8.45 M

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