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expeople1 [14]
3 years ago
7

What is the [H+] of a solution with a pH of 9.40?

Chemistry
1 answer:
LiRa [457]3 years ago
4 0

Answer:

a) 3.98 x 10^-10

Explanation:

Hello,

In this case, for the given pH, we can compute the concentration of hydronium by using the following formula:

pH=-log([H^+])

Hence, solving for the concentration of hydronium:

[H^+]=10^{-pH}=10^{-9.40}\\

[H^+]=3.98x10^{-10}M

Therefore, answer is a) 3.98 x 10^-10

Best regards.

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An element has an average atomic mass of 1.008 amu. It consists of two isotopes , one having a mass of 1.007 amu, and one having
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Answer:

The most abundant isotope is 1.007 amu.

Explanation:

Given data:

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Solution:

First of all we will set the fraction for both isotopes

X for the isotopes having mass  2.014 amu

1-x for isotopes having mass 1.007 amu

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we will use the following equation,

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1.007 x = 0.001

x= 0.001/ 1.007

x= 0.0009

0.0009 × 100 = 0.09 %

0.09 % is abundance of isotope having mass  2.014 amu because we solve the fraction x.

now we will calculate the abundance of second isotope.

(1-x)

1-0.0009 = 0.9991

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