Answer:
please find attached file
Explanation:
Answer:

Explanation:
Given data:
Mass of the man, 
Total mechanical energy, 
Height, 
Suppose there is no external force acting on the man. In this situation, the total mechanical energy (kinetic + potential) will remain steady.
Let the speed of the man at 2.6 m be <em>v</em>.
Thus,




Answer:
R/l = 0.25925 Ω / m
Explanation:
Ohm's law says that the potential difference is proportional to the product of the resistance by the current
V = I R
R = V / I
In this case, since we have two lengths, we can have two lengths, we can find the resistance for each
L = 5 m
R = 7.70 / 5.47
R = 1,408 Ω
L = 10 m
R = 7.70 / 3.25
R = 2,369 Ω
We can make a direct proportions rule (rule of three) to find the resistance per unit length
For L = 5 m
R/l = 1,408 / 5
R/l = 0.2816 Ω / m
For L = 10 m
R/l = 2,369/10
R/l = 0.2369 Ω / m
We can see that the value is similar that differs from the second decimal place, in this case the value for the longer re wire is more accurate because it has a lower joule effect.
One way also to find the average value
R/l = (0.2816 + 0.2369) / 2
R/l = 0.25925 Ω / m
Answer:
6m/s
Explanation:
momentum = mass × change in velocity
∆p =m(v)
24 = 4(v)
V =>24/4 = 6m/s
Answer:
the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Explanation:
Given the data in the question;
To determine the maximum intensity of an electromagnetic wave, we use the formula;
=
ε₀cE
²
where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )
c is the speed of light ( 3 × 10⁸ m/s )
E
is the maximum magnitude of the electric field
first we calculate the maximum magnitude of the electric field ( E
)
E
= 350/f kV/m
given that frequency of 60 Hz, we substitute
E
= 350/60 kV/m
E
= 5.83333 kV/m
E
= 5.83333 kV/m × (
)
E
= 5833.33 N/C
so we substitute all our values into the formula for intensity of an electromagnetic wave;
=
ε₀cE
²
=
× ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²
= 45 × 10³ W/m²
= 45 × 10³ W/m² × (
)
= 45 kW/m²
Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²