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Stolb23 [73]
3 years ago
14

A tree on a hillside casts a shadow 215 ft down the hill. If the angle of inclination of the hillside is 22???? to the horizonta

l and the angle of elevation of the sun is 52????, find the height of the tree.

Physics
1 answer:
krek1111 [17]3 years ago
3 0

Answer:

H=174.168ft

Explanation:

See diagram below.

First, calculate y using sine function:

sin(22)=\frac{y'}{215} \\y'=215sin(22)=80.540ft

Then, calculate x using cosine function:

cos(22)=\frac{x}{215} \\x=215cos(22)=199.345ft

Now use tangent to calculate y:

tan(52)=\frac{y+y'}{x} \\y=x*tan(52)-y'\\y = 174.168ft.

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This happens in basketball. It is known as "jump ball".
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If we put a convex lens made by crown glass <br>in Carbondia sulphide what will happen?​
7nadin3 [17]

Answer:

I don't knowI think it will break

4 0
3 years ago
How fast does water flow from a hole at the bottom of a very wide, 3.2 m deep storage tank filled with water
Nezavi [6.7K]

Answer:

the velocity of the water flow is 7.92 m/s

Explanation:

The computation of the velocity of the water flow is as follows

Here we use the Bernouli equation

As we know that

V_1 = \sqrt{2g(h_2 - h_1)}\\\\=\sqrt{2g(\Delta h)}  \\\\= \sqrt{2\times9.8\times3.2} \\\\= \sqrt{62.72}

= 7.92 m/s

Hence, the velocity of the water flow is 7.92 m/s

We simply applied the above formula so that the correct value could come

And, the same is to be considered

5 0
3 years ago
A boat of mass 250 kg is coasting, with its engine in neutral, through the water at speed 1.00 m/s when it starts to rain with i
Vera_Pavlovna [14]

Answer:

Explanation:

1. We use the conservation of momentum for before the raining and after. And also we take into account that in 0.5h the accumulated water is

100kg/h*0.5h = 50kg

p_{b}=p_{a}\\M_{b}v_{b}=(M_{b}+m_{r})v_{a}\\v_{a}=\frac{M_{b}v_{b}}{M_{b}+m_{r}}=\frac{250kg*1\frac{m}{s}}{250kg+50kg}=0.83\frac{m}{s}

2. the momentum does not conserve because the drag force of water makes that the boat loses velocity

3. If we assume that the force of the boat before the raining is

F=ma=m\frac{v-v_{0}}{t-t_{0}}=250kg\frac{1m}{s^{2}}=250N

where we have assumed that the acceleration of the boat is 1m/s{2} just before the rain starts

And if we take the net force as

F_{net}=M_{b}a_{net}=F-F_{d}=250N-bv^{2}\\F_{net}=250N-0.5N\frac{s^{2}}{m^{2}}(1\frac{m}{s})^{2}=249.5N\\a_{net}=\frac{249.5N}{M_{b}}=\frac{249.5N}{250kg}=0.99\frac{m}{s^{2}}

where we take v=1m/s because we are taking into account tha velocity just after the rain stars.

I hope this is useful for you

regards

5 0
3 years ago
Mathematically speaking, the energy of a wave is directionally proportional to the square of the amplitude of the wave Calculate
kenny6666 [7]

The energy of the wave is D) 16.0 units squared

Explanation:

The energy of a wave is directly proportional to the square of the amplitude of the wave.

Mathematically, this can be written as

E\propto A^2

where

E is the energy of the wave

A is its amplitude

For the wave in this problem, the amplitude is

A = 4 units

Therefore, assuming that the constant of proportionality is 1, the energy of this wave is

E=A^2=4^2=16 units squared

Learn more about waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

6 0
3 years ago
Read 2 more answers
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