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Stolb23 [73]
3 years ago
14

A tree on a hillside casts a shadow 215 ft down the hill. If the angle of inclination of the hillside is 22???? to the horizonta

l and the angle of elevation of the sun is 52????, find the height of the tree.

Physics
1 answer:
krek1111 [17]3 years ago
3 0

Answer:

H=174.168ft

Explanation:

See diagram below.

First, calculate y using sine function:

sin(22)=\frac{y'}{215} \\y'=215sin(22)=80.540ft

Then, calculate x using cosine function:

cos(22)=\frac{x}{215} \\x=215cos(22)=199.345ft

Now use tangent to calculate y:

tan(52)=\frac{y+y'}{x} \\y=x*tan(52)-y'\\y = 174.168ft.

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A school bus has a mass (including the driver and passengers) of 1.64 times 10^4 kg and is driving north at a speed of 15.2 km/h
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Answer:

Explanation:

Given

mass of bus along with travelers travelling in North direction is m_1=1.6\times 10^4 kg

speed of bus towards North v_1=15.2 km/h\approx 4.22\ m/s

mass of bus travelling in South direction is m_2=1.578\times 10^4 kg

speed of bus v_2=12.2 km/h\approx 3.38\ m/s

mass of each Passenger in south moving bus m_0=64.8 kg

Momentum of North moving bus

P_1=m_1\times v_1

P_1=1.6\times 10^4\times 4.22

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Momentum with south moving bus

P_2=m_2\times v_2+n\cdot m_0\times v_2

P_2=(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38

For total momentum to be towards south

P_2-P_1 should be greater than 0

thus for least value of n

P_2=P_1

(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38=6.768\times 10^4

1.578\times 10^4+n\cdot 64.8=2.0023\times 10^4

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3 years ago
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A rod 7.0 m long is pivoted at a point 2.0 m from the left end. A downward force of 50 N acts at the left end, and a downward fo
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If the rod is in rotational equilibrium, then the net torques acting on it is zero:

∑ τ = 0

Let's give the system a counterclockwise orientation, so that forces that would cause the rod to rotate counterclockwise act in the positive direction. Compute the magnitudes of each torque:

• at the left end,

τ = + (50 N) (2.0 m) = 100 N•m

• at the right end,

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