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Stolb23 [73]
4 years ago
14

A tree on a hillside casts a shadow 215 ft down the hill. If the angle of inclination of the hillside is 22???? to the horizonta

l and the angle of elevation of the sun is 52????, find the height of the tree.

Physics
1 answer:
krek1111 [17]4 years ago
3 0

Answer:

H=174.168ft

Explanation:

See diagram below.

First, calculate y using sine function:

sin(22)=\frac{y'}{215} \\y'=215sin(22)=80.540ft

Then, calculate x using cosine function:

cos(22)=\frac{x}{215} \\x=215cos(22)=199.345ft

Now use tangent to calculate y:

tan(52)=\frac{y+y'}{x} \\y=x*tan(52)-y'\\y = 174.168ft.

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1. A 17.45-N force is applied to a 3.10-kg object to accelerate it rightwards. The object encounters 15.25 N of
ollegr [7]

Answer:

please find attached file

Explanation:

3 0
3 years ago
A 59 kg man has a total mechanical energy of 150,023. J. If he is swinging downward and is currently 2.6 m above the ground, wha
Alborosie

Answer:

v = 70.95 \ m/s.

Explanation:

Given data:

Mass of the man, m = 59 \ kg

Total mechanical energy, E_{i} = 150,023 \ \rm J

Height, h = 2.6 \ m

Suppose there is no external force acting on the man. In this situation, the total mechanical energy (kinetic + potential) will remain steady.

Let the speed of the man at 2.6 m be <em>v</em>.

Thus,

E_{i} = E_{f}

E_{i} = \frac{1}{2}mv^{2} + mgh

150023 = 0.5 \times 59 \times v^{2} + 59 \times 9.80 \times 2.6

\Rightarrow \ v = 70.95 \ m/s.

6 0
3 years ago
You just landed a job as an assistant to an electrician who is working on a building site. He is making use of long single-condu
Anit [1.1K]

Answer:

R/l = 0.25925 Ω / m

Explanation:

Ohm's law says that the potential difference is proportional to the product of the resistance by the current

         V = I R

         R = V / I

In this case, since we have two lengths, we can have two lengths, we can find the resistance for each

         L = 5 m

         R = 7.70 / 5.47

         R = 1,408 Ω

         L = 10 m

         R = 7.70 / 3.25

         R = 2,369 Ω

We can make a direct proportions rule (rule of three) to find the resistance per unit length

For L = 5 m

         R/l = 1,408 / 5

         R/l = 0.2816 Ω / m

For L = 10 m

        R/l = 2,369/10

        R/l = 0.2369 Ω / m

We can see that the value is similar that differs from the second decimal place, in this case the value for the longer re wire is more accurate because it has a lower joule effect.

One way also to find the average value

       R/l = (0.2816 + 0.2369) / 2

       R/l = 0.25925 Ω / m

3 0
3 years ago
Read 2 more answers
What is the velocity of an object with a mass of 4 kg and a momentum of 24 kg.m/s
Eva8 [605]

Answer:

6m/s

Explanation:

momentum = mass × change in velocity

∆p =m(v)

24 = 4(v)

V =>24/4 = 6m/s

5 0
3 years ago
In the United States, household electric power is provided at a frequency of 60 HzHz, so electromagnetic radiation at that frequ
grigory [225]

Answer:

the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

Explanation:

Given the data in the question;

To determine the maximum intensity of an electromagnetic wave, we use the formula;

I = \frac{1}{2}ε₀cE_{max²

where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )

c is the speed of light ( 3 × 10⁸ m/s )

E_{max is the maximum magnitude of the electric field

first we calculate the maximum magnitude of the electric field ( E_{max  )

E_{max = 350/f kV/m

given that frequency of 60 Hz, we substitute

E_{max = 350/60 kV/m

E_{max = 5.83333 kV/m

E_{max = 5.83333 kV/m × ( \frac{1000 V/m}{1 kV/m} )

E_{max = 5833.33 N/C

so we substitute all our values into the formula for  intensity of an electromagnetic wave;

I = \frac{1}{2}ε₀cE_{max²

I = \frac{1}{2} × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²

I = 45 × 10³ W/m²

I = 45 × 10³ W/m² × ( \frac{1 kW/m^2}{10^3W/m^2} )

I = 45 kW/m²

Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

7 0
3 years ago
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