1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ronch [10]
3 years ago
11

The mass of Jupiter is 1.9 × 1027 and that of the sun is 1.99 × 1030. The

Physics
1 answer:
n200080 [17]3 years ago
4 0

Answer:

F = 4.147 × 10^23

v = 1.31 × 10^4

Explanation:

Given the following :

mass of Jupiter (m1) = 1.9 × 10^27

Mass of sun (m2) = 1.99 × 10^30

Distance between sun and jupiter (r) = 7.8 × 10^11m

Gravitational force (F) :

(Gm1m2) / r^2

Where ; G = 6.673×10^-11 ( Gravitational constant)

F = [(6.673×10^-11) × (1.9 × 10^27) × (1.99 × 10^30)] / (7.8 × 10^11)^2

F = [25.231 × 10^(-11+27+30)] / (60.84 × 10^22)

F = (25.231 × 10^46) / (60.84 × 10^22)

F = 3.235 × 10^(46 - 22)

F = 0.4147 × 10^24

F = 4.147 × 10^23

Speed of Jupiter (v) :

v = √(Fr) / m1

v = √[(4.147 × 10^23) × (7.8 × 10^11) / (1.9 × 10^27)

v = √32.3466 × 10^(23+11) / 1.9 × 10^27

v = √32.3466× 10^34 / 1.9 × 10^27

v = √17. 023 × 10^34-27

v = √17.023 × 10^7

v = 13047.221

v = 1.31 × 10^4

You might be interested in
A computer monitor uses 200 W of power. How much energy does it use in 10 seconds?
gavmur [86]

Answer:

<u>The correct answer is 0.556 Watts</u>

Explanation:

The computer monitor uses 200 Watts of power in an hour, that is the standard measure.

If we want to know, how much energy the computer monitor uses in one second, we will have to divide both sides of the equation into 3,600.

1 hour = 60 minutes = 3,600 seconds (60 x 60)

Energy per second = 200/3600

Energy per second = 0.0556 Watts

Therefore to calculate how much energy is used in 10 seconds, we do this:

Energy per second x 10

<u>0.0556 x 10 = 0.556 Watts</u>

<u>The computer monitor uses 0.556 Watts in 10 seconds</u>

3 0
3 years ago
Read 2 more answers
Muscular Strength exercises focus on high______and low___
Advocard [28]

Answer:

d d d d dd d d d d d dd d d d d dd d

4 0
3 years ago
Can u find the . in this?
nikklg [1K]

Answer:

Yeah it's right there from the one next to the exclamation point

4 0
3 years ago
Read 2 more answers
a battery of 5v and internal resistance of 5 ohms is connected to a resistor of 20 ohms. calculate the value of terminal voltage
Alborosie

Answer:

A bird flies 75m in 15s.Calculate its speed

7 0
2 years ago
Two horses on opposite sides of a narrow stream are pulling a barge up the stream. Each hors pulls with a force of 720N. The rop
anygoal [31]
For the answer to the question above, each horse's force forms a right angle triangle with the barge and subtends an angle of 60/2 = 30°. The resultant in the direction of the barge's motion is:
Fx = Fcos(∅)
We can multiply this by 2 to find the resultant of both horses.
Fx = 2Fcos(∅)
Fx = 2 x 720cos(30)
Fx = 1247 N
3 0
3 years ago
Other questions:
  • The risk of _______ injury increases with the total amount of physical activity. A. cardiovascular B. musculoskeletal C. cogniti
    9·1 answer
  • How do organ systems work together to deliver nutrients from food throughout the body
    8·2 answers
  • PLEASE HELP!
    12·2 answers
  • What is the period of a wave if the wavelength is 100 m and the speed is 200 m/s?
    8·2 answers
  • What is a cataclysmic comet?
    7·2 answers
  • A physicist measures the magnetic field at the center of a loop of wire with N number of turns (not a solenoid) and current I fl
    7·1 answer
  • Isaac Newton used a ____ to break white light into its component colors.
    11·2 answers
  • What formula gives the strength of an electric field, E, at a distance from a known source change?
    11·2 answers
  • A car of mass M traveling with velocity v strikes a car of mass M that is at rest. The two cars’ bodies mesh in the collision. T
    12·1 answer
  • Help please <br>the question is in the picture ​
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!