In NH4OH, the compounds that make it up are NH4+ and OH-
Therefore N exists in the ammonium form.
In the ammonium ion 4H atoms are connected to N.
N is more electronegative than H, therefore when H bonds to N, H is the more positive atom therefore each H has a charge of +1, since there are 4 H atoms the charge contributed by the 4H atoms are +1 * 4 = +4
the overall charge of NH4 is +1
Charge of N (+) +4 = +1
Charge of N = +1 - 4
Therefore oxidation state of N in NH4 is = -3
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Answer:
2CO₂ ⇄ 2CO + O₂.
Explanation:
- <em>The equilibrium constant (Keq)</em> for a reaction is the ratio of the concentration of the products to the reactants, each one is raised to each molar coefficient.
So, for Keq = [CO]²[O₂]/[CO₂]²,
It is clear that the products are CO and O₂, while the reactant is CO₂.
So, the reaction for this is:
<em>2CO₂ ⇄ 2CO + O₂.</em>
Coordination numbers are defined for the crystalline structures that tell about the numbers of atoms bonded to the central atom. The coordination number of a diamond is 4.
<h3>What is a coordination number?</h3>
A coordination number has been defining the number of the ions, atoms, and molecules that are bonded to the central atom of the crystalline compound or a complex.
The diamond has 8 carbon atoms in its one unit and its coordination number is 4 as its lattice type is face-centered cubic that has carbons at the corners and face center of the structure. One carbon contributes 1/8 hence and the faces center contributes 1/2.
Therefore, the diamond has a coordination number of 4.
Learn more about coordination numbers, here:
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Answer:
<h2>
<u>W</u><u>ater</u> covers 70 percent of earth's surface.</h2>