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3 years ago

Which compound is produced when HCl(aq) is neutralized by Ca(OH)2(aq)?

Chemistry

2 answers:

kiruha [24]3 years ago

8 0

Answer: The correct answer is Option 1.

Explanation:

Neutralization reaction is defined as the reaction in which acid reacts with a base to produce a salt along with water.

Here, HCl is an acid and $Ca(OH)_2$ is a base. When these two compounds react, the salt obtained is calcium chloride.

The equation for the above reaction is given by:

$2HCl(aq.)+Ca(OH)_2(aq.)\rightarrow CaCl_2(s)+2H_2O(l)$

Hence, the correct answer is Option 1.

loris [4]3 years ago

7 0

Ca(OH)2 +2*HCl --> CaCl2 + 2*H2O

CaCl2 (1) is the correct answer.

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Which term best describes what Donna observed? A:dew B:fog C:mist D:rain

MariettaO [177]

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3 years ago

Determine the pH of a 5x10^-4 M solution of Ca(OH)2

miss Akunina [59]

Ca(OH)₂ ==> Ca²⁺ + 2 OH-

Ca(OH)₂ is strong Bases

Therefore, the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻.

pOH = - log[ OH⁻]

pOH = - log [ 5 x 10⁻⁴ ]

pOH = 3.30

pH + pOH = 14

pH + 3.30 = 14

pH = 14 - 3.30

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3 years ago

Under a certain set of conditions, the percent yield of a reaction that produces carbon dioxide is 75.0%. What mass in grams of

ExtremeBDS [4]

Answer:

Actual yield = 20.03g

Explanation:

$% yield = 100.\frac{actual yield}{theoretical yield}$ % $yield$ = $100. \frac{actual \ yield}{theoretical \ yield}$

Actual yield = % yield.(theoretical yield) / 100

Actual yield = 75.26.7/100

Actual yield = 20.025

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3 years ago

Read 2 more answers

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amid [387]

Answer:

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Explanation:

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3 years ago

Partner Namets) For each of the following reactions carried out: Write the balanced chemical equation, the full ionic equation,

torisob [31]

Answer : The full balanced ionic equation will be,

$2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)$

Reactants are lead nitrate and potassium iodide.

Products are lead iodide and potassium nitrate.

The spectator ions are, $K^+,NO_3^-$

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When potassium iodide react with lead nitrate then it gives potassium nitrate and lead iodide as a product.

The full balanced ionic equation will be,

$2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)$

The ionic equation in separated aqueous solution will be,

$2K^+(aq)+2I^{-}(aq)+Pb^{2+}(aq)+2NO_3^{-}(aq)\rightarrow PbI_2(s)+2K^+(aq)+2NO_3^{-}(aq)$

In this equation, $K^+\text{ and }NO_3^-$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Pb^{2+}(aq)+2I^{-}(aq)\rightarrow PbI_2(s)$

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4 years ago