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borishaifa [10]
3 years ago
11

Which models of the atom does the experimental evidence from Bohr's hydrogen experiment support? Explain why these models are co

mpatible with the experimental results.
The models are Daltons, Thompsons, and Rutherfords
Chemistry
1 answer:
STALIN [3.7K]3 years ago
8 0

Answer:

Rutherfords

Explanation:

The model of the atom supported by Bohr's hydrogen experiment is the Rutherford's model of the atom.

Rutherford through his experiment on gold foil suggested the atomic model of the atom. The model posits that an atom has a small positively charged center(nucleus) where nearly all the mass is concentrated.

  • Surrounding the nucleus is the large space containing electrons.
  • In the Bohr's model of the atom, he suggested that the extranuclear space of the atom is made up of electrons in specific spherical orbits around the nucleus.
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A : The number of particle collision increases
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In a laboratory experiment, John uses a mesh to separate soil particles from water. Which technique of separation is he using?
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Salutations!

<span>In a laboratory experiment, John uses a mesh to separate soil particles from water. Which technique of separation is he using?

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3 0
3 years ago
Write a nuclear reaction for the neutron-induced fission of u−235 to form xe−144 and sr−90.
rusak2 [61]

Answer:

235/92U+10n→144/54Xe+90/38Sr+2/10n

Explanation:

  • The nuclear reaction for the neutron-induced fission of u−235 to form xe−144 and sr−90 is represented by;

235/92U+10n→144/54Xe+90/38Sr+2/10n

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3 years ago
The electrons in an insulator are tightly bound to their atoms.
Murrr4er [49]
If its a true or false statement . the answer is true 
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3 years ago
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In a reaction between 6.0 g of oxygen gas, 4.0 g of hydrogen gas, and 5.0 g of solid sulfur at standard temperature and pressure
nikitadnepr [17]

Answer:

The limiting reagent is the O₂

Explanation:

We can think, this reaction

2O₂(g) + H₂(g) + S(s)  →  H₂SO₄

Mole of each = Mass / molar mass

6 g / 32 g/m = 0.187 mole O₂

4g / 2 g/m = 2 mole H₂

5g / 32.06 g/m = 0.156 mole S

Ratio between reactants is 2:1:1, 1:2:1, 1:1:2

For 2 mole of O₂, I need to react 1 mol of H₂ and 1 mol of S

0.187 mole of O₂, I need (the half)

0.093 mole of H₂ and 0.093 mole of S

For 1 mole of H₂, I need to react 2 mole of O₂ and 1 mol of S

2 mole of H₂, I need (the double of O₂ and the same for S)

4 mole of O₂ ; 2 mole of S

For 1 mol of S, I need to react 1 mol of H₂ and 2 mole of O₂

0.156 mole I need the same amount for H₂ and the double for O₂

0.156 mole of H₂ and 0.312 mole of O₂

In both cases, I can't make react, all the mass of oxygen, so this is the limiting reagent.

6 0
3 years ago
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