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2 years ago

Which of the following is true regarding the properties of light?

1 answer:

6 0

Light having a dual nature and acting like both a wave and a particle is the correct statement in this scenario.

<h3>What is Light?</h3>

This refers to the electromagnetic radiation found in the electromagnetic spectrum that is perceived by the human eye and has a dual nature. It doesn't require a medium for its propagation unlike sound.

The dual nature of light is as a result of it behaving like a photon which is why it travels in straight lines.

It also behave like a wave because it undergoes processes such as reflection, refraction etc which are common to waves.

Read more about Light here brainly.com/question/1363382

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A train moving at a constant speed is passing a stationary observer on a platform. On one of the train cars, a flute player is c

Ilya [14]

Answer:

Explanation:

We shall apply the formula of Doppler effect here

F( APPARENT) = F( REAL ) X V/(V + Vs) [ v is velocity of sound and Vs is velocity of source.

415 = 440 X 343/343+Vs

142345 + 415Vs = 150920

415 V₀ = 8575

V₀ = 20.66 m/s.

8 0

3 years ago

The uniform dresser has a weight of 91 lb and rests on a tile floor for which μs = 0.25. If the man pushes on it in the horizont

Rudiy27

Answer:

F = 22.75 lb

μ₁ = 0.15

Explanation:

The smallest force required to move the dresser must be equal to the force of friction between the man and the dresser. Therefore,

F = μR

F = μW

where,

F = Smallest force needed to move dresser = ?

μ = coefficient of static friction = 0.25

W = Weight of dresser = 91 lb

Therefore,

F = (0.25)(91 lb)

<u></u>

Now, for the coefficient of static friction between shoes and floor, we use the same formula but with the mas of the man:

F = μ₁W₁

where,

μ₁ = coefficient of static friction between shoes and floor

W₁ = Weight of man = 151 lb

Therefore,

22.75 lb = μ₁ (151 lb)

μ₁ = 22.75 lb/151 lb

7 0

3 years ago

Speed deamplifier. Block 1 of mass m1 slides along an x axis on a frictionless floor at speed 4.00 m/s. Then it undergoes a oned

alisha [4.7K]

Answer:

29J

Explanation:

Please see attachment .

7 0

4 years ago

What should be the spring constant k of a spring designed to bring a 1200 kg car to rest from a speed of 85 km/h so that the occ

borishaifa [10]

Answer:

k = 5178.8 N/m

Explanation:

As we know that spring mass system will oscillate at angular frequency given as

$\omega = \sqrt{\frac{k}{m}}$

now we have

$\omega = \sqrt{\frac{k}{1200}}$

now the maximum acceleration of the spring block system is at its maximum compression state which is given as

$a = \omega^2 A$

here A= maximum compression of the spring

so here in order to find maximum compression of the spring we will use energy conservation as we know that initial total kinetic energy of the car will convert into spring potential energy

$\frac{1}{2}mv^2 = \frac{1}{2}kA^2$