All categories

4 years ago

MathPhys Help pls Tysm

Physics

2 answers:

andrew-mc [135]4 years ago

7 0

Answer:

8.75

Explanation:

HACTEHA [7]4 years ago

3 0

Answer:

8.75

Explanation:

First, find the force of friction.

Kinetic energy = work done by friction

½ mv² = Fd

½ (3.9 kg) (2.9 m/s)² = F (1.4 m)

F = 11.7 N

Next, find the distance at the new velocity.

Kinetic energy = work done by friction

½ mv² = Fd

½ (3.9 kg) (2.5 × 2.9 m/s)² = (11.7 N) d

d = 8.75 m

You might be interested in

Someone fires a 0.04 kg bullet at a block of wood that has a mass of 0.5 kg. (The block of wood is sitting on a frictionless sur

lidiya [134]

Answer:

22.22m/s

Explanation:

The momentum before a collision = momentum after collision so...

work out the momentum of the first object (the bullet)

its p = mv

0.04 kg × 300 m/s = 0.54 kg × v

rearrange this to find v which is 0.04 x 300 = 12

so 12 = 0.54 x v

12/0.5 = v

v = 22.22m/s

hope this helps!

7 0

3 years ago

Electrons in excited hydrogen atoms are in the

Sidana [21]

I can see three different transitions here:

3 --> 1

3 --> 2
followed by
2 --> 1 .

So we should expect to see three different 'colors'
being emitted from this excited mob.

4 0

3 years ago

What is the most likely elevation of point B?<br>a. 150 ft<br>b. 200 ft<br>c. 125 ft<br>d. 225 ft

zepelin [54]

Answer:

Explanation:

erm i think its 225 ft?

7 0

4 years ago

Read 2 more answers

A water strider bug is supported on the surface of a pond by surface tension acting along the interface between the water and th

Alik [6]

Answer:

minimum interface length = 1.36 mm

Explanation:

given data

weight of the bug = $10^{-4}$ N

solution

we will apply here Surface Tension formula that is

Surface Tension ,σ = Force ÷ length ........................1

and we consider here surface tension for water is 7.34 × $10^{-2}$ N/m

so that here minimum interface length needed to support the bug is

minimum interface length = Force ÷ σ

minimum interface length = $10^{-4}$ ÷ 7.34 × $10^{-2}$

minimum interface length = 1.36 mm

4 0

3 years ago

The water from a fire hose follows a path described by y equals 3.0 plus 0.8 x minus 0.40 x squared (units are in meters). If

ivanzaharov [21]

Explanation:

It is given that, the water from a fire hose follows a path described by equation :

$y=3+0.8x-0.4x^2$ ........(1)

The x component of constant velocity, $v_x=5\ m/s$

We need to find the resultant velocity at the point (2,3).

Let $\dfrac{dx}{dt}=v_x$ and $\dfrac{dy}{dt}=v_y$

Differentiating equation (1) wrt t as,

$\dfrac{dy}{dt}=0.8\times \dfrac{dx}{dt}-0.8x\times \dfrac{dx}{dt}$

$v_y=0.8\times v_x-0.8x\times v_x$

$v_y=0.8v_x(1-x)$

When x = 2 and $v_x=5\ m/s$

So,

$v_y=0.8\times 5\times (1-2)$

$v_y=-4\ m/s$

Resultant velocity, $v=\sqrt{v_x^2+v_y^2}$

$v=\sqrt{5^2+(-4)^2}$

v = 6.4 m/s

So, the resultant velocity at point (2,3) is 6.4 m/s. Hence, this is the required solution.

8 0

3 years ago