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Snezhnost [94]
3 years ago
14

MathPhys Help pls Tysm

Physics
2 answers:
andrew-mc [135]3 years ago
7 0

Answer:

8.75

Explanation:

HACTEHA [7]3 years ago
3 0

Answer:

8.75

Explanation:

First, find the force of friction.

Kinetic energy = work done by friction

½ mv² = Fd

½ (3.9 kg) (2.9 m/s)² = F (1.4 m)

F = 11.7 N

Next, find the distance at the new velocity.

Kinetic energy = work done by friction

½ mv² = Fd

½ (3.9 kg) (2.5 × 2.9 m/s)² = (11.7 N) d

d = 8.75 m

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A student pushes on a crate with a force of 100 Newtons directed to the right.
romanna [79]

Answer:

100N

Explanation:

Newton's third law of motion

For every action, there is an equal and opposite reaction.

Therefore 100N of force is exerted by the crate on student as a reaction to his action

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3 years ago
A wire that is 0.36 meters long moves perpendicularly through a magnetic field at a speed of 0.21 meters/second. The induced emf
dmitriy555 [2]
0.034 newtons/amp·meter

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what is the source of centripetal force that planet requires revolving around the sun on what basis the factor does that was the
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Answer:

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5 0
3 years ago
Give an example of nonpoint-source pollution
Ket [755]
Nonpoint source pollution is pollution that affects bodies of water, so remembering this can help in the future with this type of question. Some examples of nonpoint source pollution are; Excess fertilizers and herbicides, oil and toxic chemical runoff, as well as sediment from eroding stream banks. I hope this helps :)
8 0
3 years ago
You throw a 20-n rock vertically into the air from ground level. you observe that when it is a height 15.4 m above the ground, i
gayaneshka [121]

I believe there are two things which we asked to find here:

1. its speed just as it left the ground

2. find its maximum height

 

Solutions:

1. We use the formula:

ΔKE = - ΔPE

where KE is kinetic energy = ½ mv^2, and PE is potential energy = m g h, Δ = change

Therefore:

½ m (v2^2 – v1^2) = m g (h1 – h2)

at initial point, point 1: h1 = 0, v1 = ?

at final point, point 2: h2 = 15.4 m, v2 = 24.2 m/s

½ (24.2^2 – v1^2) = 9.8 (0 – 15.4)

585.64 – v1^2 = -301.84

-v1^2 = 887.48

v1 = 29.8 m/s

So the rock was travelling at 29.8 m/s as it left the ground.

 

2. The maximum height (hmax) reached is calculated using the formula:

v1^2 = 2 g hmax

Rewriting in terms of hmax:

hmax = v1^2 / 2 g

hmax = (29.8)^2 / (2 * 9.8)

hmax = 45.3 m

Therefore the rock reached a maximum height of 45.3 meters.

4 0
3 years ago
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