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kakasveta [241]

3 years ago

12

Please help me fr fr !

1 answer:

Furkat [3]3 years ago

6 0

The answer is A because it describes both toy cars

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How strongly the planet you're on pulls on you is your

IrinaK [193]

The size of the forces between you and the planet you're on is
your weight on that planet.

Don't forget that you pull the planet with a force equal to the force
that the planet pulls on you. Your weight on Earth is the same as
the Earth's weight on you !

6 0

3 years ago

Read 2 more answers

The maximum tension that a 0.80 m string can tolerate is 15 N. A 0.35-kg ball attached to this string is being whirled in a vert

zimovet [89]

Answer:

v=5.86 m/s

Explanation:

Given that,

Length of the string, l = 0.8 m

Maximum tension tolerated by the string, F = 15 N

Mass of the ball, m = 0.35 kg

We need to find the maximum speed the ball can have at the top of the circle. The ball is moving under the action of the centripetal force. The length of the string will be the radius of the circular path. The centripetal force is given by the relation as follows :

$F=\dfrac{mv^2}{r}$

v is the maximum speed

$v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{15\times 0.8}{0.35}} \\\\v=5.86\ m/s$

Hence, the maximum speed of the ball is 5.86 m/s.

3 0

3 years ago

6, P 14 are consecutive terms in an AP<br>find the value of P.

xenn [34]

In an arithmetic progression, consecutive terms differ by the same value.

So, we have

$P-6 = 14-P$

which reflects the fact that the difference between P and 6 must be the same than the one between P and 14.

The equation solves to

$2P=20\iff P=10$

And in fact, if you start with

$6, 10, 14$

every pair of consecutive terms differ by 4.

6 0

3 years ago

What is measurement?

Semmy [17]

Answer:

How long or wide something is

Explanation:

5 0

2 years ago

A projectile is fired from the origin (at y = 0 m) as shown in the diagram. The initial velocity

Viktor [21]

Answer:

-26 m/s.

Explanation:

Hello,

In this case, since the vertical initial velocity is 26 m/s and the vertical final velocity is 0 m/s at P, we compute the time to reach P:

$t=\frac{0m/s-26m/s}{-9.8m/s^2} =2.65s$

With which we compute the maximum height:

$y=26m/s*2.65s-\frac{1}{2}*9.8m/s^2*(2.65s)^2 \\\\y=34.5m$

Therefore, the final velocity until the floor, assuming P as the starting point (Voy=0m/s), turns out:

$v_f=\sqrt{0m/s-(-9.8m/s^2)*2*34.5m}\\ \\v_f=-26m/s$

Which is clearly negative since it the projectile is moving downwards the starting point.

Regards.

3 0

3 years ago