Question

A light bulb is rated at 25 W when operated at 120 V. How much charge enters (and leaves) the light bulb in 1. 0 min?

Answer 1

The amount of charge enters (and leaves) is 12 Coulomb.

How can we find the value of the amount of charge enters (and leaves)?

Here we are using the formula,

$I=\frac{P}{V}$ and $Q= I \times t$

We are given,

P = Power of the light bulb = 25 Watt.

V = The amount of voltage where the light bulb operated = 120 Volt.

t= The time when charge enters (and leaves) the light bulb = 1.0 min = $(1 \times 60) second$ = 60 S

We have to find,

I= The amount of current flows in the light bulb.

Q= The amount of charge enters (and leaves) the light bulb.

Now we substitute the values of known parameters in the first equation, we find that,

$I=\frac{P}{V}=\frac{25}{120}$

Or, $I= 0.20 A$

The amount of current flows in the light bulb is 0.20 Ampere.

Now, we put the value of I in the second equation,

$Q= I \times t= 0.20 \times 60$

Or, $Q=12 C$

So, from the above calculations we can see that the amount of charge enters (and leaves) the light bulb is 12 Coulomb.

Learn more about the light bulb:

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