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3 years ago

What is the percent composition of C4H10? (4 points)

Chemistry

1 answer:

Marina CMI [18]3 years ago

6 0

Answer:82.7% C and 17.3% H

Explanation:

C4 = 12.0107g/mol x 4 = 48.0428 g/mol

H10 = 1.00794 g/mol x 10 = 10.0794 g/mol

Molar Mass of Butane, C4H10 = 48.0428 g/mol + 10.0794 g/mol= 58.1222 g/mol

percent composition of Carbon is = ( mass of carbon contained in butane / molar mass of Butane) x 100

=(48.0428 /58.1222) x 100% = 0.8265 x 100

=82.65% =82.7% of Carbon.

Percent composition of Hydrogen = (mass of Hydrogen contained in Butane / molar mass of Butane )x 100

( 10.0794/58.122 ) x 100% =0.1734 x 100

= 17.3% OF Hydrogen.

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Answer:

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Explanation:

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The expression for Gibbs energy is:

ΔGrxn = ∑Gproducts - ∑Greactants

Where

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M = 0

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$lnK=-\frac{deltaG_{rxn} }{RT}$

Where

ΔGrxn = 6.7 kJ/mol = 6700 J/mol

T = 298 K

R = 8.314 J/mol K

$lnK=-\frac{6700}{8.314*298} =-2.704\\K=0.066$

c) The equilibrium pressure of O₂ over M is:

$K=P_{O2} ^{3/2} \\P_{O2}=K^{2/3} =0.066^{2/3} =0.16atm$

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2 years ago

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Answer:

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Explanation:

It is given that,

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The average atomic mass for element Z is given by :

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