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slavikrds [6]
2 years ago
5

A 20.0-mL sample of 0.115 M sulfurous acid (H2SO3) solution is titrated with 0.1014 M KOH. At what added volume of base solution

does each equivalence point occur
Chemistry
1 answer:
Vitek1552 [10]2 years ago
8 0

Answer:

Explanation:

20mL = 0.020L

0.115M = mol/0.02L

mol=0.0023

equivalence point → mols of weak acid = mols of strong base

0.1014 = 0.0023/volume

volume = 0.02268 L → 22.68 mL

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Transition metals tend to
bonufazy [111]
I think the answer is D all of the above.
7 0
3 years ago
In the chemical reaction C + H20 = CO + H2, what are the
drek231 [11]
B , your products are on the right side of the reaction. The reactants are on the left side
7 0
3 years ago
In an aqueous solution, 42% of a substance dissociates to release hydronium ions. Which of the following statements is true for
const2013 [10]

Answer: The statement it is a weak acid is true for the substance.

Explanation:

An acid that dissociates completely when dissolved in water to give hydrogen (H^{+}) or hydronium (H_{3}O^{+}) ions is called a strong acid.

For example, HCl is a strong acid.

HCl + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}

An acid that dissociates partially or weakly when dissolved in water to given hydrogen or hydronium ions is called a weak acid.

For example, CH_{3}COOH is a weak acid.

CH_{3}COOH \rightleftharpoons CH_{3}COO^{-} + H_{3}O^{+}

A strong base is a base which when dissolved in water then it dissociates completely to give hydroxide ions.

For example, NaOH is a strong acid.

A weak base is a base which when dissolved in water then it dissociates partially or weakly to give hydroxide ions.

For example, NH_{3} is a weak base.

Hence, in an aqueous solution where 42% of a substance dissociates to release hydronium ions shows that the dissociation is less than 50%. This means that substance is dissociating weakly so, it is a weak acid.

Thus, we can conclude that the statement it is a weak acid is true for the substance.

5 0
3 years ago
Given the balanced equation representing a reaction: 2h2o(l) + 571.6 kJ -> 2h2(g) + o2(g). What occurred as a result of this
Ivan

Answer: option D) energy was absorbed and entropy increased.


Explanation:


1) Given balanced equation:


2H₂O (l) + 571.6 kJ → 2 H₂ (g) + O₂(g).


2) Being the energy placed on the side of the reactants means that the energy is used (consumed or absorbed). This is an endothermic reaction.


So, the first part is that energy was absorbed.


3) As for the entropy, it is a measure of the disorder or radomness of the system.


Since, two molecules of liquid water were transformed into three molecules of gas, i.e. more molecules and more kinetic energy, therefore the new state has a greater degree of radomness, is more disordered, and you conclude that the entropy increased.


With that, you have shown that the right option is D) energy was absorbed and increased.

7 0
4 years ago
72.0 grams of water how many miles of sodium with react with it?
Flura [38]

Answer:

\large \boxed{\text{8.00 mol}}

Explanation:

We will need a balanced chemical equation with masses, moles, and molar masses.

1. Gather all the information in one place:

Mᵣ:                  18.02

            2Na + H₂O ⟶ 2NaOH + H₂

m/g:                72.0  

2. Moles of H₂O

\text{Moles of H$_{2}$O} = \text{72.0 g H$_{2}$O} \times \dfrac{\text{1 mol H$_{2}$O}}{\text{18.02 g  H$_{2}$O}} = \text{3.996 mol H$_{2}$O}

3. Moles of Na

The molar ratio is 2 mol Na/1 mol H₂O.

\text{Moles of Na} =  \text{3.996 mol H$_{2}$O} \times \dfrac{\text{2 mol Na}}{\text{1 mol H$_{2}$O}} = \textbf{8.00 mol Na}\\\\\text{The water will react with $\large \boxed{\textbf{ 8.00 mol}}$ of Na}

7 0
3 years ago
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