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slavikrds [6]
2 years ago
5

A 20.0-mL sample of 0.115 M sulfurous acid (H2SO3) solution is titrated with 0.1014 M KOH. At what added volume of base solution

does each equivalence point occur
Chemistry
1 answer:
Vitek1552 [10]2 years ago
8 0

Answer:

Explanation:

20mL = 0.020L

0.115M = mol/0.02L

mol=0.0023

equivalence point → mols of weak acid = mols of strong base

0.1014 = 0.0023/volume

volume = 0.02268 L → 22.68 mL

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A student is studying the boiling points of six different liquids and finds results with consistently higher boiling points than
almond37 [142]

Answer:

Large molecules tend to have greater boiling points because the London dispersion forces are stronger within.

Explanation:

4 0
2 years ago
How many mL of 0.506 M HClare needed to dissolve 9.85 g of BaCO3?
Blababa [14]

Answer:

197mL of 0,506M HCl

Explanation:

The reaction of HCl + BaCO₃ is:

BaCO₃(s) + 2HCl → BaCl₂(aq) + CO₂ + H₂O.

The moles of BaCO₃ in 9,85 g are:

9,85 g of BaCO₃ × \frac{1mol}{197,34 g} = <em>0,0499 moles of BaCO₃</em>

As 1 mol of BaCO₃ reacts with two moles of HCl, for a complete reaction of BaCO₃ to dissolve this compound in water you need:

0,0499 moles of BaCO₃ × \frac{2molHCl}{1molBaCO_{3}} =<em> 0,0998 moles of HCl</em>

If you have a 0,506M HCl, you need to add:

0,0998 moles of HCl× \frac{1L}{0,506moles} = 0,197 L ≡ 197mL

I hope it helps!

8 0
3 years ago
The mass of proton<br>1) 1072* 10-28​
jasenka [17]

Answer:

Mass of proton is

<h2>1.6726219 × 10-27 Kg</h2>

HOPE U UNDERSTOOD

MARK AS BRAINLIEST ONE

THANKS

IF ANY DOUBTS? PLS COMMENT

5 0
3 years ago
A sample contains 16. 75 g of the radioisotope U-236 and 50. 25 g of its daughter isotope, Th-232. How long did it take for deca
garri49 [273]

The time taken for the isotope to decay is 46 million years.

We'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:

  • Original amount (N₀) = 50.25 g
  • Amount remaining (N) = 16.75
  • Number of half-lives (n) =?

2ⁿ = N₀ / N

2ⁿ = N₀ / N

2ⁿ = 50.25 / 16.75

2ⁿ = 3

Take the log of both side

Log 2ⁿ = 3

nLog 2 = Log 3

Divide both side by log 2

n = Log 3 / Log 2

n = 2

Finally, we shall determine the time.

  • Half-life (t½) = 23 million years
  • Number of half-lives (n) = 2
  • Time (t) =?

t = n × t½

t = 2  × 23

t = 46 million years

Learn more about half-life: brainly.com/question/25927447

8 0
3 years ago
Read 2 more answers
Please help me which one
mel-nik [20]
Non of the above because protons and neutrons don’t mix with each one there
3 0
2 years ago
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