The answer is D. The input force is equal to the output force.
I just did test and got it right
In the presence of air resistance, a watermelon is launched into the air with 100 j of kinetic energy.
Its kinetic energy is less than 100 J when it reaches its starting point. Its kinetic energy decreases as it encounters air resistance and returns to its starting point. In actuality, some of the energy has been lost because of air resistance. Since we use the ball's original height as a point of reference, there is no potential energy when the ball is in its initial state of motion, and K is its kinetic energy. This total energy is conserved if there is no air resistance, therefore when the ball returns to its starting position, its kinetic energy will remain at 100.
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Answer:
1) The Newton's law the Hulk is most closely demonstrating is <em>the Third Law of motion</em>
Newton's third law of motion states that action and reaction are equal and opposite.
2) The reason why the Newton's Law the Hulk is most closely demonstrating is the Newton's Third Law of Motion is that according to Newton's Third Law of motion, forces exist in pairs, the action of the Hulk when he leaps upward by pushing against the the Earth (which can be assumed stationary in relation to the Hulk), is equal to the reaction of the Earth, which moves down slightly, away from its initial position.
However, due to the large mass of the Earth, compared to the mass of the Hulk, the downward motion of the Earth due to the reaction force (equal to the force with which the Hulk leaps) is negligibly small, such that the Earth can absorb the Hulk's leap force by reacting mainly locally, at the leap point by forming a crater, while the Earth in general, remains in the same place
Explanation:
<span>b. It ensures that measurements are taken from two points
that are very far apart.
Measurements taken six months apart are the farthest apart
that an astronomer can ever get ... they're on opposite sides
of the Earth's orbit !</span>
The fraction of the kinetic energy of the ball lost during the collision is 
.
The given parameters;
- <em>initial speed of the ball, = vi</em>
- <em>final momentum of the ball, Pf = ¹/₃Pi</em>
The initial and final momentum of the ball is calculated as;
The initial and final kinetic energy of the ball is calculated as;
The change in the kinetic energy is calculated as;
Thus, the fraction of the kinetic energy of the ball lost during the collision is .
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