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The length of the wire is 36 m.
<u>Explanation:</u>
Given, Diameter of sphere = 6 cm
We know that, radius can be found by taking the half in the diameter value. So,

Similarly,

We know the below formulas,


When equating both the equations, we can find length of wire as below, where 


The
value gets cancelled as common on both sides, we get

The
value gets cancelled as common on both sides, we get

Acetic acid is a weak acid and sodium hydroxide is strong base. Salts of the two will hydrolyse to give basic solution. So, at neutral point, pH of the solution will be greater than 8.
Answer:
Large above ground mausoleums were not common in the elite Shang burials.
Explanation:
Large, above the ground mausoleums were not common so the answer is option B.