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Dafna1 [17]
2 years ago
7

A box moves 5\,\text m5m5, start text, m, end text horizontally when a force, F =10\,\text NF=10NF, equals, 10, start text, N, e

nd text is applied at an angle, \theta =150\degreeθ=150°theta, equals, 150, degree as shown below. A dark grey box slides along a light grey horizontal surface. the box has a force vector F pulling up and to the left on it. A displacement vector d extends rightwards form the center of the box. The angle between vectors F and d is labeled theta. A dark grey box slides along a light grey horizontal surface. the box has a force vector F pulling up and to the left on it. A displacement vector d extends rightwards form the center of the box. The angle between vectors F and d is labeled theta. What is the work done on the box by FFF during the displacement?
Physics
2 answers:
Tpy6a [65]2 years ago
7 0

Answer:

-43J

Explanation:

Irina18 [472]2 years ago
5 0

Answer:

??

Explanation:

not completely sure hold on

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What is the volume of an object that has a density of 65g/cm3 and a mass of 130g.
lora16 [44]

Density <em>ρ</em> is mass <em>m</em> per unit volume <em>v</em>, or

<em>ρ</em> = <em>m</em> / <em>v</em>

Solving for <em>v</em> gives

<em>v</em> = <em>m</em> / <em>ρ</em>

So the given object has a volume of

<em>v</em> = (130 g) / (65 g/cm³) = 2 cm³

5 0
3 years ago
Answer the question fast please​
AnnZ [28]

Answer:

1

Explanation:

d = m \div v  \\ m = 0.8 \: v = 80\% \: also \: 0.8 \\ d = 0.8 \div 0.8 \\ d = 1

6 0
3 years ago
Which of the following are NOT examples of digital information storage?
VikaD [51]
Vinyl records because it’s not a secure information storage
3 0
2 years ago
Read 2 more answers
A 66-kg base runner begins his slide into second base when he is moving at a speed of 3.4 m/s. The coefficient of friction betwe
Helen [10]

Answer:

a ) = 381.48 J

b )=  84.25 cm

Explanation:

Kinetic energy of the runner

= 1/2 m v²

= .5 x 66 x 3.4²

= 381.48 J

The final kinetic energy of the runner is zero .

Loss of mechanical energy

= 381.48 J

This  loss in  mechanical energy is due to action of frictional force .

b )

Let s be the distance of slide

deceleration due to frictional force

= μmg/m

.7 x 66 x 9.8 / 66

a = - 6.86 m s⁻¹

v² = u² - 2 a s

0 = 3.4² - 2x6.86 s

s = 3.4² / 2x6.86

= .8425 m

84.25 cm

5 0
2 years ago
If the velocity of an object is zero at one instant, what is true about the acceleration of that object
Charra [1.4K]

Answer:

I. The acceleration could be positive.

II. The acceleration could be zero.

III. The acceleration could be negative.

Explanation:

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

Velocity = \frac{distance}{time}

If the velocity of an object is zero at one instant, then the acceleration of that object may have the following characteristics;

I. The acceleration could be positive.

II. The acceleration could be zero.

III. The acceleration could be negative.

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

a = \frac{v  -  u}{t}

Where,

a is acceleration measured in ms^{-2}

v and u is final and initial velocity respectively, measured in ms^{-1}

t is time measured in seconds.

8 0
2 years ago
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