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2 years ago

Why must protein digesting enzymes be stored in the inactive form

Chemistry

1 answer:

max2010maxim [7]2 years ago

8 0

Answer:

To shield the organs and glands from the enzymes' digestion, protein digesting enzymes are released in an inactive state. If they are discharged in an active state, they begin digesting the glands that transport them as well as the release site.

Explanation:

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Question 55 pm

Law Incorporation [45]

Answer:

They are magnetic lines and theses lines depict the invisible magnetic field around the magnet! Hope this helps I got it right on my quiz:)

Explanation:

3 0

3 years ago

From a 2.875 g sample containing only iron, sand, and salt, 0.660 g of iron and 1.161 g of sand were separated and recovered. Wh

Serjik [45]

Answer:

36.66%

Explanation:

Step 1: Given data

Mass of iron: 0.660 g

Mass of sand: 1.161 g

Mass of the sample: 2.875 g

Mass of salt: ?

Step 2: Calculate the mass of salt

The mass of the sample is equal to the sum of the masses of the components.

m(sample) = m(iron) + m(sand) + m(salt)

m(salt) = m(sample) - m(iron) - m(sand)

m(salt) = 2.875 g - 0.660 g - 1.161 g

m(salt) = 1.054 g

Step 3: Calculate the percent of salt in the sample

We will use the following expression.

%(salt) = m(salt) / m(sample) × 100%

%(salt) = 1.054 g / 2.875 g × 100% = 36.66%

7 0

3 years ago

Cobalt chloride Select one: a. Does not exist as a hydrate b. Forms a single hydrate which may be pink or blue c. Forms differen

Anarel [89]

Answer:

c. Forms different hydrates which have different colors

Explanation:

4 0

3 years ago

How many moles of oxygen atoms are in 7.9E-1 moles of CO_2

Ilya [14]

Answer:

The number of moles of O atom in $(7.9\times10^{-1})$ mol of $CO_{2}$ = 1.6

Explanation:

1 molecule of $CO_{2}$ contains 2 atoms of O

So, $(6.023\times 10^{23})$ molecules of $CO_{2}$ contains $(2\times6.023\times10^{23})$ atoms of O.

We know that 1 mol of an atom/molecule/ion represents $6.023\times10^{23}$ numbers of atoms/molecules/ions respectively.

So, $(6.023\times 10^{23})$ molecules of $CO_{2}$ is equal to 1 mol of $CO_{2}$ .

$(2\times6.023\times10^{23})$ atoms of O is equal to 2 moles of O atom.

Hence, 1 mol of $CO_{2}$ contains 2 moles of O atom.

Therefore, $(7.9\times10^{-1})$ mol of $CO_{2}$ contains $(2\times7.9\times10^{-1})$ moles of O atom or 1.6 moles of O atom.

3 0

3 years ago

Read the article. Use your understanding to answer the questions that follow. What type of source is this article? primary or se

valkas [14]

Answer: option C

Explanation:

3 0

3 years ago

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