A. ask him/her to pull over and offer to drive (if you have your license.)
B. ask him/her to call someone to come pick you guys up.
C. call a cab.
Answer:
Consider the two rotating pulley-like systems above. They are identical in every way EXCEPT the mass of the pulley on the left is concentrated on the outside edge (ring or hoop shape), while the mass of pulley on the right is evenly distributed throughout the pulley (disc or cylinder shape). Given R =0.15m, M =0.6 kg, and m= 0.5 kg. Both pulley systems are initially at rest and the block masses are a height of 0. 8m above the ground.
Explanation:
If both masses are released at the same time, which pulley will hit the ground first
Answer: 20360 N
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<h2>Answer</h2>
1m/s
<h2>Explanation</h2>
Given that:
<em>Mass of first blob = 2kg = m1</em>
<em>Velocity of blob = 4m/s = v1</em>
<em>Mass of second blob = 6kg = m2</em>
<em>Velocity of blob = 0m/s = v2</em>
<em />
To find:
<em>Final velocity = Vf</em>
<em />
<em>This question is of inelastic collision which is any collision between objects in which some energy is lost.</em>
<em />
<h3>Formula to be use:</h3><h2>(m1*v1) + (m2*V2) = Vf(m1 + m2)</h2>
(2*4) + (6*0) = Vf(2+6)
8 + 0 = Vf(8)
8 = Vf(8)
Vf = 1 m/s
So the speed of two blobs immediately after colliding = 1 m/s
