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kkurt [141]
2 years ago
15

What differentiable functions have an arc length on the interval [a,b] given by the following integrals? note that the answers a

re not unique. give all functions that satisfy the conditions.
Physics
1 answer:
klemol [59]2 years ago
8 0

What differentiable functions have an arc length on the interval [a,b] given by the following integrals? Note that the answers are not unique. Give all functions that satisfy the conditions.

<h3>What are differentiable functions? </h3>

In mathematics, a differentiable function of one real variable is a function that has a derivative at each point in its domain. In other words, the graph of a differentiable function has a non-vertical tangent line at each interior point in its domain.

A smooth, differentiable function lacks any breaks, angles, or cusps (it is locally well approximated as a linear function at each interior point).

If the derivative f'(x 0) exists, a function f is said to be differentiable at x0 if x0 is an inner point in the domain of the function.

In other words, the point (x0, f(x0)) on the graph of f has a non-vertical tangent line. If f is differentiable at every point along U, then U is said to be differentiable.

If the derivative off is also a continuous function over the domain of the function ff, then f is said to be continuously differentiable.

In general, if f’s initial k derivatives are f prime (x), f prime (x), and lots, f(k)(x), then f is said to be of class Ck. f prime (x), f prime (x), lots, and f (k) prime (x) exist and are continuous across the function’s domain.

To know more about such differential function question, visit:

brainly.com/question/14290915

#SPJ4

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Between which of the following surfaces with the force of friction be smallest
Elina [12.6K]

Answer:

Smother places........

8 0
3 years ago
A sample of copper with a mass of 1.80 kg, initially at a temperature of 150.0°C, is in a well-insulated container. Water at a t
user100 [1]

Answer:

the mass of water is 0.3 Kg

Explanation:

since the container is well-insulated, the heat released by the copper is absorbed by the water , therefore:

Q water + Q copper = Q surroundings =0 (insulated)

Q water = - Q copper

since Q = m * c * ( T eq - Ti ) , where m = mass, c = specific heat, T eq = equilibrium temperature and Ti = initial temperature

and denoting w as water and co as copper :

m w * c w * (T eq - Tiw) = - m co * c co * (T eq - Ti co) =  m co * c co * (T co - Ti eq)

m w = m co * c co * (T co - Ti eq) / [ c w * (T eq - Tiw) ]

We take the specific heat of water as c= 1 cal/g °C = 4.186 J/g °C . Also the specific heat of copper can be found in tables → at 25°C c co = 0.385 J/g°C

if we assume that both specific heats do not change during the process (or the change is insignificant)

m w = m co * c co * (T eq - Ti co) / [ c w * (T eq - Tiw) ]

m w= 1.80 kg *  0.385 J/g°C ( 150°C - 70°C) /( 4.186 J/g°C ( 70°C- 27°C))

m w= 0.3 kg

7 0
4 years ago
A screen is placed 1.60 m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.40 c
Lunna [17]

Answer:

distance between the two second-order minima is 2.8 cm

Explanation:

Given data

distance = 1.60 m

central maximum = 1.40 cm

first-order diffraction minima = 1.40 cm

to find out

distance between the two second-order minima

solution

we know that fringe width = first-order diffraction minima /2

fringe width = 1.40 /2 = 0.7 cm

and

we know fringe width of first order we calculate slit d

β1 = m1λD/d

d = m1λD/β1

and

fringe width of second order

β2 = m2λD/d

β2 = m2λD / ( m1λD/β1 )

β2 = ( m2 / m1 ) β1

we know the two first-order diffraction minima are separated by 1.40 cm

so

y = 2β2 = 2 ( m2 / m1 ) β1

put here value

y = 2 ( 2 / 1 ) 0.7

y = 2.8 cm

so distance between the two second-order minima is 2.8 cm

6 0
3 years ago
A single output device has failed while the remainder of the PLC system is functioning normally The indicator light on the outpu
Dmitry_Shevchenko [17]

Answer:

check the point where the output device's field wiring is connected to the output rack. ( C )

Explanation:

Given that an indicator light on the output module is indicating that a signal has been sent to the output point where the failed single output device is connected , the best line of action to properly indicate the output device that has filed in the PLC system, is to check the point where the output device's field wiring is connected to the output rack in the PLC system.

A PLC system is a computer control system ( especially Industrial ) that helps in the monitoring the states of input and output devices in an industry.

8 0
3 years ago
Help plss i just need it plss​
Travka [436]

Answer:

ooh thanks but don't give me advise

4 0
3 years ago
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