If the shopping cart is parallel to the ground, the weight is acting vertically downward, then force is equal to weight. The normal force will be acting perpendicular to the ground,and acting upward opposite of the weight.
<span>3.834 m/s.
In this problem we need to have a centripetal force that is at least as great as the gravitational attraction the object has. The equation for centripetal force is
F = mv^2/r
and the equation for gravitational attraction is
F = ma
Since m is the same in both cases, we can cancel it out and then set the equations equal to each other, so
a = v^2/r
Substitute the known values (radius is diameter/2) and solve for v
9.8 m/s^2 <= v^2/1.5 m
14.7 m^2/s^2 <= v^2
3.834057903 m/s <= v
So the minimum velocity needed is 3.834 m/s.</span>
Answer:
The answer is 34.119m
Explanation:
You need to pay attention to the word "uniformly". It means there is no acceleration thus the physics of this problem respond to the uniform rectilinear motion equations:
- Xf = Xo + vt
- v = constant
- a = 0
where:
- v = velocity (speed)
- t = time
- a = acceleration
Xf = 0 + (15.3)(2.23)
Xf = 34.119m
The initial velocity of particle is 7.568 m/s
Given:
Acceleration = a = 6.14 m/s2
Time = t = 0.300 s.
final velocity = v = 9.41 m/s.
To Find:
initial velocity = u
Solution: Velocity is the prime indicator of the position as well as the rapidity of the object.
v = u + at
u = v - at = 9.41 - 6.14*0.3 = 7.568 m/s
Hence, initial velocity of particle is 7.568 m/s
Learn more about Velocity here:
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