The answer to this question is a) sulfur
Answer:
The tension is 
Explanation:
From the question we are told that
The total mass is 
The radius is 
The density of air is 
Generally the upward force acting on the balloon is mathematically represented as

=> 
=> 
Here V is the volume of the spherical helium filled balloon which is mathematically represented as

=> 
=> 
So


Answer:
Explanation:
Given
For first case
launch angle 
at highest point 


For second case

at highest Point velocity is 

as there is no acceleration in x direction therefore horizontal velocity is same