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VikaD [51]
2 years ago
12

If you are being tailgated and need to make a stop, you should

Engineering
1 answer:
alexandr402 [8]2 years ago
8 0

If you are being tailgated and need to make a stop, you should:

B. flash your brake lights ahead of time.

C. slow sooner to make a gradual stop.

<h3>What is tailgating?</h3>

Tailgating can be defined as an act which typically involves a tailgater driving dangerously close behind another vehicle that is in front.

This ultimately implies that, a tailgating vehicle is a hazard to any driver because when he or she brakes suddenly, it may result in the tailgater hitting him or her from the rear.

In this context, we can infer and logically deduce that if you are being tailgated and need to make a stop, you should flash your brake lights ahead of time and slow sooner to make a gradual stop.

Read more on tailgating vehicle here: brainly.com/question/14287208

#SPJ1

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Malia is working with aluminum wire. while working with this type of wire, she must remember to a. always use pressure-type term
Y_Kistochka [10]

Answer:

B

Explanation:

Aluminium doesn't rust unless exposed to copper for a duration of time.

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Think for a moment about the potential problems with big data that the speaker mentioned:
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TWO SENTENCES!!!! What are the roles of an engineer?
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Answer:

An engineer nomaly cretea things designed by others.They also help repare stuff like cars sorry bout the gammr

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Given: A graphite-moderated nuclear reactor. Heat is generated uniformly in uranium rods of 0.05m diameter at the rate of 7.5 x
sineoko [7]

Answer:

The maximum temperature at the center of the rod is found to be 517.24 °C

Explanation:

Assumptions:

1- Heat transfer is steady.

2- Heat transfer is in one dimension, due to axial symmetry.

3- Heat generation is uniform.

Now, we consider an inner imaginary cylinder of radius R inside the actual uranium rod of radius Ro. So, from steady state conditions, we know that, heat generated within the rod will be equal to the heat conducted at any point of the rod. So, from Fourier's Law, we write:

Heat Conduction Through Rod = Heat Generation

-kAdT/dr = qV

where,

k = thermal conductivity = 29.5 W/m.K

q = heat generation per unit volume = 7.5 x 10^7 W/m³

V = volume of rod = π r² l

A = area of rod = 2π r l

using these values, we get:

dT = - (q/2k)(r dr)

integrating from r = 0, where T(0) = To = Maximum center temperature, to r = Ro, where, T(Ro) = Ts = surface temperature = 120°C.

To -Ts = qr²/4k

To = Ts + qr²/4k

To = 120°C + (7.5 x 10^7 W/m³)(0.025 m)²/(4)(29.5 W/m.°C)

To = 120° C + 397.24° C

<u>To = 517.24° C</u>

5 0
4 years ago
Consider a voltage v = Vdc + vac where Vdc = a constant and the average value of vac = 0. Apply the integral definition of RMS t
Anna11 [10]

Answer:

Proof is as follows

Proof:

Given that , V = V_{ac} + V_{dc}

<u>for any function f with period T, RMS is given by</u>

<u />RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[f(t)]^{2} } \, dt  }<u />

In our case, function is V = V_{ac} + V_{dc}

RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[V_{ac} + V_{dc}]^{2} } \, dt  }

Now open the square term as follows

RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[V_{ac}^{2} + V_{dc}^{2} + 2V_{dc}V_{ac}] } \, dt  }

Rearranging  terms

RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {V_{dc}^{2}  } \, dt  + \frac{1}{T}\int\limits^T_0 {V_{ac}^{2}  } \, dt  + \frac{1}{T}\int\limits^T_0 {2V_{dc}V_{ac}  } \, dt  }

You can see that

  • second term is square of RMS value of Vac
  • Third terms is average of VdcVac and given is that                      average of  V_{ac}V_{dc} = 0

so

RMS = \sqrt{\frac{1}{T}TV_{dc}^{2}   + [RMS~~ of~~ V_{ac}]^2 }

RMS = \sqrt{V_{dc}^{2}   + [RMS~~ of~~ V_{ac}]^2 }

So it has been proved that given expression for root mean square (RMS) is valid

7 0
3 years ago
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