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2 years ago

Answer below, only if you know the answer, please. :)

Physics

1 answer:

frez [133]2 years ago

8 0

D. All the three bulbs connected in the series circuit will burn at equal brightness.

<h3>What is series circuit?</h3>

A series circuit comprises a path along which the whole current flows through each component.

A parallel circuit comprises branches so that the current divides and only part of it flows through any branch.

In a series circuit, same current flows in each component of the circuit.

V = I(R₁ + R₂ + R₃)

where;

R₁ is resistance of bulb 1
R₂ is resistance of bulb 2
R₃ is resistance of bulb 3

If all the bulbs have equal resistance, they will burn at equal brightness.

Thus, all the three bulbs connected in the series circuit will burn at equal brightness.

The correct option is D.

Learn more about series circuit here: brainly.com/question/19865219

#SPJ1

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Which of the following statements is false?

vladimir1956 [14]

An excited atom can return to its ground state by absorbing electromagnetic radiation is false about the electromagnetic radiation.

Option B

<u>Explanation</u>:

In the scope of modern quantum theory, the term Electromagnetic radiation is identified as the movement of photons through space. Almost all the sources of energy that we utilize today such as coal, oil, etc are a product of electromagnetic radiation which was absorbed from the sun millions of years ago.

Various properties of electromagnetic radiations are a directly proportional relationship between the energy and the frequency, Inverse proportionality between frequency and the wavelength, etc. Hence, we can conclude that an "excited atom" can never return to its ground state by assimilating electromagnetic radiation and the 2nd statement is false.

4 0

3 years ago

Dr. John Paul Stapp was U.S. Air Force officer who studied the effects of extreme deceleration on the human body. On December 10

Nuetrik [128]

Answer:

acceleraions 5.76g and 20.55g

Explanation:

This constant acceleration exercise can be solved using the kinematic equations in one dimension

Vf = Vo + a t

As part of the rest Vo = 0

a = Vf / t

a = 282/5

a = 56.4 m / s2

In relation to the acceleration of gravity

a ’= a / g = 56.4 / 9.8

a ’= 5.76g

To calculate the acceleration to stop we use the same formula

a2 = 282 / 1.40

a2 = 201.4 m / s2

This acceleration of gravity acceleration function is

a2 ’= 201.4 / 9.8

a2 ’= 20.55g

3 0

4 years ago

A 1.65 kg mass stretches a vertical spring 0.260 m If the spring is stretched an additional 0.130 m and released, how long does

Irina-Kira [14]

Answer:

The system will take approximately 0.255 seconds to reach the (new) equilibrium position.

Explanation:

We notice that block-spring system depicts a Simple Harmonic Motion, whose equation of motion is:

$y(t) = A\cdot \cos \left(\sqrt{\frac{k}{m} }\cdot t +\phi\right)$ (1)

Where:

$y(t)$ - Position of the mass as a function of time, measured in meters.

$A$ - Amplitude, measured in meters.

$k$ - Spring constant, measured in newtons per meter.

$m$ - Mass of the block, measured in kilograms.

$t$ - Time, measured in seconds.

$\phi$ - Phase, measured in radians.

The spring is now calculated by Hooke's Law, that is:

$k = \frac{m\cdot g}{\Delta y}$ (2)

Where:

$g$ - Gravitational acceleration, measured in meters per square second.

$\Delta y$ - Deformation of the spring due to gravity, measured in meters.

If we know that $m=1.65\,kg$ , $g = 9.807\,\frac{m}{s^{2}}$ and $\Delta y = 0.260\,m$ , then the spring constant is:

$k = \frac{(1.65\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{0.260\,m}$

$k = 62.237\,\frac{N}{m}$

If we know that $A = 0.130\,m$ , $k = 62.237\,\frac{N}{m}$ , $m=1.65\,kg$ , $x(t) = 0\,m$ and $\phi = 0\,rad$ , then (1) is reduced into this form:

$0.130\cdot \cos (6.142\cdot t)=0$ (1)

And now we solve for $t$ . Given that cosine is a periodic function, we are only interested in the least value of $t$ such that mass reaches equilibrium position. Then:

$\cos (6.142\cdot t) = 0$