The time it takes Jane to catch up with Don if Jane is traveling at 10 k.p.h and don at 6 k.p.h is: 2.5 h
The formula and procedure we will use to solve this problem is:
Tr = x/(v2-v1)
Where:
Information about the problem:
Applying the reach time formula we get:
Tr = x/(v2-v1)
Tr = 10 km/(10 km/h- 6 km/h)
Tr = 10 km/(4 km/h)
Tr = 2.5 h
<h3>What is velocity?</h3>It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).
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Mass of the block = 1.4 kg
Weight of the block = mg = 1.4 × 9.8 = 13.72 N
Normal force from the surface (N) = 13.72 N
Acceleration = 1.25 m/s^2
Let the coefficient of kinetic friction be μ
Friction force = μN
F(net) = ma
μmg = ma
μg = a
μ =
μ =
μ = 0.1275
Hence, the coefficient of kinetic friction is: μ = 0.1275