don is 10 kilometers ahead of jane, and both are traveling forward. how long will it take jane to catch up with don if jane is t
1 answer:
The time it takes Jane to catch up with Don if Jane is traveling at 10 k.p.h and don at 6 k.p.h is: 2.5 h
The formula and procedure we will use to solve this problem is:
Tr = x/(v2-v1)
Where:
- x = separation distance
- Tr = reach time
- v2 = velocity of the faster mobile
- v1 = velocity of the slowest mobile
Information about the problem:
- x = 10 km
- v2 = 10 km/h
- v1 = 6 km/h
- Tr=?
Applying the reach time formula we get:
Tr = x/(v2-v1)
Tr = 10 km/(10 km/h- 6 km/h)
Tr = 10 km/(4 km/h)
Tr = 2.5 h
<h3>What is velocity?</h3>It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).
Learn more about velocity at: brainly.com/question/80295?source=archive
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