Question

don is 10 kilometers ahead of jane, and both are traveling forward. how long will it take jane to catch up with don if jane is traveling at 10 k.p.h and don at 6 k.p.h. ?

Answer 1

The time it takes Jane to catch up with Don if Jane is traveling at 10 k.p.h and don at 6 k.p.h is: 2.5 h

The formula and procedure we will use to solve this problem is:

Tr = x/(v2-v1)

Where:

• x = separation distance
• Tr = reach time
• v2 = velocity of the faster mobile
• v1 = velocity of the slowest mobile

Information about the problem:

• x = 10 km
• v2 = 10 km/h
• v1 = 6 km/h
• Tr=?

Applying the reach time formula we get:

Tr = x/(v2-v1)

Tr = 10 km/(10 km/h- 6 km/h)

Tr = 10 km/(4 km/h)

Tr = 2.5 h

What is velocity?

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

Learn more about velocity at: brainly.com/question/80295?source=archive

#SPJ4