Here's a formula that's simple and useful, and if you're really in
high school physics, I'd be surprised if you haven't see it before.
This one is so simple and useful that I'd suggest memorizing it,
so it's always in your toolbox.
This formula tells how far an object travels in how much time,
when it's accelerating:
Distance = (1/2 acceleration) x (Time²).
D = 1/2 A T²
For your student who dropped an object out of the window,
Distance = 19.6 m
Acceleration = gravity = 9.8 m/s²
D = 1/2 G T²
19.6 = 4.9 T²
Divide each side by 4.9 : 4 = T²
Square root each side: 2 = T
When an object is dropped in Earth gravity,
it takes 2 seconds to fall the first 19.6 meters.
Answer:
Zero
Explanation:
It is given that,
A person swims to the other end of a 20m long pool and back.
We need to find his displacement.
Displacement = shortest path covered
He reaches at the same position as from where he has started. It means the shortest path covered is equal to 0 i.e. his displacement is zero.
Answer:
<em>600N(downwards)</em>
Explanations
<em>600N(downwards)</em>
Mas of the person = 60kg
Acceleration due to gravity = -10m/s²
To get the earths pull on the person, we will use the Newton second law of motion;
Force = mass * acceleration;
Force = 60 * -10
Force- -600N
<em>Hence the earth gravitational pull on the person is 600N(downwards). It is downwards due to the negative sign.</em>
<em></em>
deceleration or rėtardation i’m pretty sure (it won’t let me say the second word but it’s correct)
Answer:
μ = 0.6
Explanation:
given,
speed of car = 29.7 m/s
Radius of curve = 50 m
θ = 30.0°
minimum static friction = ?
now,
writing all the forces acting along y-direction
N cos θ - f sinθ = mg
N cos θ -μN sinθ = mg
now, writing the forces acting along x- direction
N sin θ + f cos θ = F_{net}
N cos θ + μN sinθ = F_{net}
taking cos θ from nominator and denominator
now, inserting all the given values
μ = 0.6
