Answer:
Torque is 93 Nm anticlockwise.
Explanation:
We have value of torque is cross product of position vector and force vector.
A force of 38 N, directed 30° above the x axis in the x-y plane.
Force, F = 38 cos 30 i + 38 sin 30 j = 32.91 i + 19 j
A particle is located on the x axis 4.9 m and we have to find torque about the origin on the particle.
Position vector, r = 4.9 i
Torque, T = r x F = 4.9 i x (32.91 i + 19 j) = 4.9 x 19 k = 93.1 k Nm
So Torque is 93 Nm anticlockwise.
Answer:
Net force of the object is zero.
Explanation:
When an object is going to the left at constant velocity, this means there is no acceleration. Hence, no force. Had there been force,acceleration had been inevitable. Therefore, we can say that when an object moves with a constant velocity and in same direction, the net force on the object is zero.
Answer:
F - M a force exerted by scales on student
M a = M (9.8 + 4.9) m/s^2 upwards chosen as positive
a = 1.5 g net acceleration of student due to force of scales
W =M g weight of student (actual weight)
Wapp = M 1.5 * g apparent weight (on scales) of student
Explanation:
hope it will help you understand, if you have any questions just let me know.
it's how much it weighs and how much force is pushing on it like a egg if i drop it the weigh can cause it to break and how much force the gravity is pushing on it.
