Answer:
If sunspots are active, more solar flares will result creating an increase in geomagnetic storm activity for Earth.
Explanation:
I ask mom
The density of a solid object that has a mass of 1.62 lb and a volume of 190 mL is 3.87g/mL.
<h3>How to calculate density?</h3>
Density is the measure of the mass of matter contained by a unit volume. It can be calculated by dividing the mass of the substance by its volume.
According to this question, a solid object is said to have a mass of 1.62 lb and a volume of 190 mL.
1 pound = 453.592 grams
1.62 Ibs is equivalent to 734.82 grams
Density of the solid object = 734.82 grams ÷ 190 mL
Density = 3.87g/mL
Therefore, the density of a solid object that has a mass of 1.62 lb and a volume of 190 mL is 3.87g/mL.
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Answer:
0.0159m
Explanation:
9 M
Explanation:
Lead(II) chloride,
PbCl
2
, is an insoluble ionic compound, which means that it does not dissociate completely in lead(II) cations and chloride anions when placed in aqueous solution.
Instead of dissociating completely, an equilibrium rection governed by the solubility product constant,
K
sp
, will be established between the solid lead(II) chloride and the dissolved ions.
PbCl
2(s]
⇌
Pb
2
+
(aq]
+
2
Cl
−
(aq]
Now, the molar solubility of the compound,
s
, represents the number of moles of lead(II) chloride that will dissolve in aqueous solution at a particular temperature.
Notice that every mole of lead(II) chloride will produce
1
mole of lead(II) cations and
2
moles of chloride anions. Use an ICE table to find the molar solubility of the solid
PbCl
2(s]
⇌
Pb
2
+
(aq]
+
2
Cl
−
(aq]
I
−
0
0
C
x
−
(+s)
(
+
2
s
)
E
x
−
s
2
s
By definition, the solubility product constant will be equal to
K
sp
=
[
Pb
2
+
]
⋅
[
Cl
−
]
2
K
sp
=
s
⋅
(
2
s
)
2
=
s
3
This means that the molar solubility of lead(II) chloride will be
4
s
3
=
1.6
⋅
10
−
5
⇒
s
= √
1.6
4
⋅
10
−
5 =
0.0159 M
Medical Insurance and Premium are the answers to your questions.
Answer: Option (B) is the correct answer.
Explanation:
It is known that flow of electrons is known as current. Also, we know that electrons carry a negative charge.
Therefore, when parallel wires carrying current in the same direction then due to the same charge there will be repulsion between the electrons.
Thus, we can conclude that Ampere showed that parallel wires carrying current in the same direction would repel each other.
