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Answer:
456 kJ
Step-by-step explanation:
CH₄ + 2Cl₂ ⟶ CCl₄ + 2H₂ ; ΔH = 45.6 kJ
Treat the heat as if it were a product in the equation. Then use the molar ratio (45.6 kJ/2 mol Cl₂) in the usual way.
Amount of energy = 20 mol Cl₂ × (45.6 kJ/2 mol Cl₂) = 456 kJ
You must add 456 kJ to react 20 mol of chlorine with excess methane.
Answer:
<u> </u><u>85.952 ml</u> needed to titrate the excess complexing reagent .
Explanation:
Lets calculate
After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml
As the number of moles of =
=
=0.01172
Molarity =
=
=0.000586 moles
Excess of EDTA = concentration of EDTA - concentration of CoSO4
= 0.009005 - 0.000586
= 0.008419 M
As M1V1 ( Excess of EDTA ) = M2V2
V2 =85.952 ml
Therefore , <u>85.952 ml </u> needed to titrate the excess complexing reagent .
The resistance of the heating element is 21.61 Ω
Given
The power dissipated = 1500 W
Voltage = 180 V
We know that
Power = Voltage * Current
⇒ Power / Voltage = Current
⇒ 1500 W/180 V = Current
⇒ 8.33 A = Current
In order to calculate the resistance of the heating element. We Have to apply the formula
Power = (Current)^2 * Resistance
⇒ Resistance = Power / (Current)^2
⇒ Resistance = 1500 W/ (8.33) ^2
⇒ Resistance = 21.61 Ω
Hence the resistance of the heating element is 21.61 Ω
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