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VikaD [51]
2 years ago
8

Cssk12.net bookmarks X Courseware G

Chemistry
1 answer:
nexus9112 [7]2 years ago
3 0
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Write a balanced net ionic equation for the following double replacement reaction
shtirl [24]

Answer:

Ba²⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s)  

Explanation:

There are three steps you must follow. You must write the:

  • Molecular equation
  • Ionic equation
  • Net ionic equation

A. Molecular equation

BaCl₂(aq) + Na₂SO₄(aq) ⟶ BaSO₄(s) + 2NaCl(aq)

B. Ionic equation

You write all the soluble substances as ions.

Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)

C. Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

Ba²⁺(aq) + <u>2Cl⁻(aq) </u>+ <u>2Na⁺(aq</u>) + SO₄²⁻(aq) ⟶ BaSO₄(s) + <u>2Na⁺(aq)</u> + <u>2Cl⁻(aq) </u>

The net ionic equation is

Ba²⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s)  

3 0
3 years ago
What at the three different variables in density?
tatyana61 [14]

Answer:Independent, dependent, and controlled variables.

Explanation:

8 0
2 years ago
A 0.307-g sample of an unknown triprotic acid is titrated to the third equivalence point using 35.2 ml of 0.106 m naoh. calculat
Jet001 [13]
Triprotic acid is a class of Arrhenius acids that are capable of donating three protons per molecule when dissociating in aqueous solutions.  So the chemical reaction as described in the question, at the third equivalence point, can be show as: H3R + 3NaOH ⇒ Na3R + 3H2O, where R is the counter ion of the triprotic acid. Therefore, the ratio between the reacted acid and base at the third equivalence point is 1:3. 
The moles of NaOH is 0.106M*0.0352L = 0.003731 mole.  So the moles of H3R is 0.003731mole/3=0.001244mole.
The molar mass of the acid can be calculated: 0.307g/0.001244mole=247 g/mol.
6 0
3 years ago
How could natural selection lead to speciation?
Harlamova29_29 [7]

Answer:

Speciation can be driven by evolution, which is a process that results in the accumulation of many small genetic changes called mutations in a population over a long period of time. ... Natural selection can result in organisms that are more likely to survive and reproduce and may eventually lead to speciation.

I hope it's helpful!

6 0
2 years ago
The number of electrons in n=1 and n=2 shells of aluminum are
harina [27]

Answer:

n=1 holds two electrons and n=2 holds eight electrons.

Explanation:

Hello

In this case, since the atomic number of aluminum is 13, its electron configuration is:

Al^{13}: 1s^2,2s^2,2p^6,3s^2,3p^1

In such a way, we can see that the level n=1 is filled with two electrons since the subshell s is able to hold two electrons and the level n=2 is also filled but with eight electrons as s holds two whereas p holds 6. Moreover, n=3 is holding three electrons.

Best regards.

5 0
3 years ago
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