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3 years ago

6

Need a bit of help with this. Fill in the coefficients, explain your answer.

1 answer:

sp2606 [1]3 years ago

4 0

Answer:

4Fe + 3O₂ → 2Fe₂O₃

General Formulas and Concepts:

<u>Chemistry - Reactions</u>

Balancing Reactions

Explanation:

<u>Step 1: Define</u>

RxN: Fe + O₂ → Fe₂O₃

<u>Step 2: Balance</u>

We need to balance both Fe and O.

LCM of 2 and 3 is 6:

Fe + 3O₂ → 2Fe₂O₃

We now need the same amount of Fe on both sides:

4Fe + 3O₂ → 2Fe₂O₃

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What happens to light as it hits the surfaces of two media at an angle?

vivado [14]

Answer:

Explanation:

When a light ray strikes the interface between two mediums, it is refracted through an angle that depends on the index of refraction of each material and the ray's angle of incidence, as measured relative to the normal (perpendicular) between the surfaces.

3 0

2 years ago

A closed 5.00 L container is filled with a mixture of 4.00 moles of hydrogen gas, 8.00 moles of oxygen, 12.0 moles of helium, an

rjkz [21]

Answer:

24.44 atm

Explanation:

Considering that this gas mixture behaves like an ideal gass, and that all component gases are ideal gases, we can use:

PV=nRT

Then:

P=nRT/V

Where:

n= N° of moles

R= gas constant= 0.082 Lt*atm/K*mol

T= temperature (in Kelvin)

V = volume (in Lt)

Finally, statement says:

T = 25°C = 298 K

V = 5 Lt

n = 8 moles (for O₂)

P = [8 molx(0.082 Lt*atm/K*mol)x298 K]/5 Lt

P = 24.44 atm would be the pressure due to O₂ (partial pressure of the oxygen)

7 0

3 years ago

Where does the “fizz” in soda come from?

andre [41]

Answer:

chemical reaction

Explanation:

u dont know bc are noob and me not noob i are pro

8 0

2 years ago

Read 2 more answers

Chromium is manufactured by heating a mixture of chromium(III) oxide with aluminium powder.

IrinaVladis [17]

Answer:

a) $m_{Al} = 17.82 g$

b) $m_{Cr} = 34.32 g$

c) $m_{Cr} = 3.42 kg$

d) $m_{Cr} = 3.42 tonnes$

Explanation:

The reaction is:

Cr₂O₃(s) + 2Al(s) → 2Cr(s) + Al₂O₃(s)

a) To find the Al mass needed to react with 50 g of Cr₂O₃, we need to calculate the number of moles of Cr₂O₃:

$n_{Cr_{2}O_{3}} = \frac{m_{Cr_{2}O_{3}}}{M_{Cr_{2}O_{3}}}$

Where:

$m_{Cr_{2}O_{3}}$ : is the mass = 50 g

$M_{Cr_{2}O_{3}}$ : is the molar mass = 2*52+3*16 = 152 g/mol

$n_{Cr_{2}O_{3}} = \frac{50 g}{152 g/mol} = 0.33 moles$

Now, the estoichiometric relation between Cr₂O₃ and Al is 1:2, so:

$\eta_{Al} = \frac{2}{1}*\eta_{Cr_{2}O_{3}} = 2*0.33 moles = 0.66 moles$

Hence, the mass of Al is:

$m_{Al} = 0.66 moles*27 g/mol = 17.82 g$

b) The stoichiometric relation from Cr₂O₃ and Cr is 1:2, hence:

$\eta_{Cr} = \frac{2}{1}*0.33 moles = 0.66 moles$

Thus, the mass of Cr is:

$m_{Cr} = 0.66 moles*52 g/mol = 34.32 g$

c) The number of moles of Cr₂O₃ with a mass of 5 kg is:

$n_{Cr_{2}O_{3}} = \frac{5 \cdot 10^{3} g}{152 g/mol} = 32.89 moles$

So, the mass of Cr is:

$m_{Cr} = 2*32.89 moles*52 g/mol = 3.42 kg$

d) The mass of Cr produced from 5 tonnes of Cr₂O₃ is:

$m_{Cr} = 2*\frac{5 \cdot 10^{6} g}{152 g/mol}*52 g/mol = 3.42 tonnes$

I hope it helps you!

7 0

3 years ago

Len [333]

Answer:

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Explanation:

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4 0

2 years ago