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Tju [1.3M]
3 years ago
15

What does Newton's second law of motion describe?

Physics
2 answers:
wolverine [178]3 years ago
7 0

Answer:

As the other person said it, relationship between force, mass, and acceleration.

Explanation:

Lyrx [107]3 years ago
3 0
Newton's second law of motion describes the relationship
between force, mass, and acceleration.

These days, we usually write it as

                   Force  =  (mass) x (acceleration) .
You might be interested in
A toy car pushed across the floor is observed to slow down and stop based on Newton’s first law of motion what is the best concl
Maksim231197 [3]

An object in motion eventually stops because of friction.

<h3>What is Newton’s first law of motion?</h3>

Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or continue its moving in a straight line at constant speed unless force is applied on it.

So we can conclude that An object in motion eventually stops is the correct answer.

Learn more about law here: brainly.com/question/820417

3 0
2 years ago
Smaller mammals use proportionately more energy than larger mammals; that is, it takes more energy per gram to power a mouse tha
timama [110]

Answer:

10,200 Cal. per day

Explanation:

The mouse consumes 3.0 Cal each day, and has a mass of 20 grams. We can use this data to obtain a ratio of energy consumption per mass

\frac{3.0 \ Cal}{20 g} = 0.15 \frac{Cal}{g}.

For the human, we need to convert the 68 kilograms to grams. We can do this with a conversion factor. We know that:

1 \ kg = 1000 \ g,

Now, we can divide by 1 kg on each side

\frac{1 \ kg}{1 \ kg} = \frac{1000 \ g}{1 \ kg},

1 = \frac{1000 \ g}{1 \ kg}.

Using this conversion factor, we can obtain the mass of the human in grams, instead of kilograms. First, lets take:

mass_{human} = 68 \ kg

We can multiply this mass for the conversion factor, we are allowed to do this, cause the conversion factor equals 1, and its adimensional

mass_{human} = 68 \ kg * \frac{1000 \ g}{1 \ kg}

mass_{human} = 68,000 g

Now that we know the mass of the human on grams, we can multiply for our ratio of energy consumption

68,000 \ g * 0.15 \frac{Cal}{g} = 10,200 \ Cal

So, we would need 10,200  Cal per day.

3 0
3 years ago
What’s the temperature 414 K in degrees Celsius?
Alborosie

Answer:

414K − 273.15 = 140.85°C

Explanation:

7 0
3 years ago
Read 2 more answers
Calculate the equivalent resistance for both circuits. Series circuit: 2 Ω and 4 Ω Parallel circuit: 2 Ω and 4 Ω Which circuit h
goldenfox [79]
Equivalent resistance is also known as the overall resistance. 

For resistors in a series circuit, the total resistance is computed using the formula:

R_{T} = R_{1}+ R_{2}+ R_{3}... R_{n}

In other words, you just add up the resistance of each resistor in the series circuit. In your case you only have two resistors. You have 2Ω and 4Ω. So all you need to do is add that up. 

R_{T} = R_{1}+ R_{2}
R_{T} = 2 + 4=6

The total resistance of the series circuit is 6Ω

In a parallel circuit you get the total resistance using the formula:
\frac{1}{R_{T}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}...+\frac{1}{R_{n}}

First you get the sum of all fractions and at the end take the reciprocal of the resulting fraction and divide. So let us take your problem into consideration where you have two resistors that have a resistance of 2Ω and 4Ω.

\frac{1}{R_{T}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}
\frac{1}{R_{T}} = \frac{1}{2}+\frac{1}{4}
\frac{1}{R_{T}} = \frac{2}{4}+\frac{1}{4}
\frac{1}{R_{T}} = \frac{3}{4}

Get the reciprocal of the resulting fraction 3/4 and then divide. The reciprocal of 3/4 is 4/3.

4/3 = 1. 33Ω

So if you compare the equivalent resistance of the two circuits, the series circuit has a higher equivalent resistance. 
3 0
3 years ago
Read 2 more answers
determinar el valor de la velocidad que lleva un cuerpo cuya masa es 3kg y su energia cinetica es de 400Joule
Korolek [52]

Answer:

This is what they said in english if everyone was wondering

Explanation:

determine the value of the velocity carried by a body whose mass is 3kg and its kinetic energy is 400Joule

6 0
3 years ago
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