Question

A long solenoid that has 1000 turns uniformly distributed over a length of 0.400 m produces a magnetic field of magnitude 1.00 ×10⁻⁴T at its center. What current is required in the windings for that to occur?

Answer 1

0.03185A current is required in the windings for that to occur.

• Solenoids are essentially coils of cord. These generate a magnetic subject which strives a pressure over a steel element.A solenoid is a fundamental time period for a coil of cord that we use as an electromagnet.
• We additionally consult with the tool which could convert electric power into mechanical power as a solenoid.

• Actually it generates a magnetic subject for developing linear movement from the electrical cutting-edge. With using a magnetic subject.

• Magnetic field at the centre of a solenoid of length 'L' having 'N' number of turns with a current 'I' is given by $B=\frac{u_0NI}{L}$   ...(1)

It is given that 1000 turns uniformly distributed over a length of 0.400 m produces a magnetic field of magnitude 1.00 ×10⁻⁴T .

Putting above values in equation (1) , we get

$1.00\times10^{-4}=\frac{4\pi \times10^{-7}\times1000I}{0.400} \\\\I=\frac{1.00\times10^{-4} \times0.400}{4\pi \times1000} \\\\I=0.03185A$

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