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hodyreva [135]
2 years ago
14

Kim is ice-skating going 4.6 m/s. What is her velocity after 10 seconds ?

Physics
1 answer:
MArishka [77]2 years ago
6 0

This is a uniform rectilinear motion (MRU) exercise.

To start solving this exercise, we obtain the following data:

<h3><u>Data:</u></h3>
  • v = 4.6 m/s
  • d = ¿?
  • t = 10 sec

To calculate distance, speed is multiplied by time.

We apply the following formula: d = v * t.

We substitute the data in the formula: the <u>speed is equal to 4.6 m/s,</u> the <u>time is equal to 10 s</u>, which is left as follows:

\bf{d=4.6\dfrac{m}{\not{s}}*10\not{s} }

\bf{d=46 \ m}

Therefore, the speed at 10 seconds is 46 meters.

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John often sees squiggly lines when he looks at a bright sky or white paper. His doctor says that they are called eye floaters,
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Answer- It's B, i double checked it on a few websites

8 0
2 years ago
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A rifle bullet with a mass of 11.5 g traveling toward the right at 251 m/s strikes a large bag of sand and penetrates it to a de
BabaBlast [244]

To look for the acceleration, it will come from:

vf^2=v0^2+2ad 
where:
vf = final velocity = 0 
v0 = initial velocity =251 m/s 
a = acceleration 
d= distance traveled = 0.237 m 

0=251^2+2a(0.237 ) 
a= -251 ^2 / (2*0.237) =-132 913.502 m/s/s 

we find the force from: 

F = ma = 0.0115kg*(-1.32x10^5m/s/s) = -1518 N 

the negative sign shows that the force is in the direction contradictory the bullet's motion

5 0
3 years ago
the velocity of a car traveling in the positive direction decreases from 32 m/s to 24 m/s in 4 seconds. what is the average acce
anastassius [24]

Answer:

a=-2m/sec^2

Negative sign shows that velocity of the car is decreases at a constant rate

Explanation:

We have given velocity of the car is decreases from 32 m /sec to 24 m/sec in 4 second

So initial velocity of the car u = 32 m /sec

And finally car reaches to a velocity of 24 m/sec

Time taken to change in velocity = 4 sec

So final velocity v = 24 m/sec

From first equation of motion v = u+at

So 24=32+a\times 4

a=-2m/sec^2

Negative sign shows that velocity of the car is decreases at a constant rate

6 0
2 years ago
Two 1.0 kg masses are 4.0 m apart on a frictionless table. Each has 1.0μC of charge. Part A What is the magnitude of the electri
9966 [12]

Force between two charges is given by

F =\frac{kq_1q_2}{r^2}

F =\frac{9*10^9* 1* 10^{-6}* 1 * 10^{-6}}{4^2}

F = 5.625 * 10^{-4} N

Now in order to find the acceleration of each mass

we can use

F = ma

5.625 * 10^{-4} = 1 * a

a= 5.625 * 10^{-4} m/s^2

8 0
3 years ago
Read 2 more answers
(1) find the density of a substance if the mass of the substance is 150kg and dimension 20mby10mby5m
Vikentia [17]

Answer:

0.15kg/m³

Explanation:

Density = mass/ volume

Given that

Mass = 150kg

Note that volume = length x breadth x height

Volume = 20 x 10 x 5

Volume = 1000m³

Density = mass ➗ volume

Density = 150kg ➗ 1000m³

Density = 0.15kg/m³

I hope this was helpful, Please mark as brainliest  

3 0
3 years ago
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