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V125BC [204]
3 years ago
9

Which would most likely cause the cylinder head temperature and engine oil temperature gauges to exceed their normal operating r

anges?
Physics
1 answer:
dusya [7]3 years ago
3 0

Answer: Using fuel that has a lower-than-specified fuel rating.

Explanation:

Most likely, what causes the cylinder head temperature and engine oil temperature gauges to exceed their normal operating ranges is using fuel that has a lower-than-specified fuel rating. This can lead to detonation of the engine which is the tendency for the fuel to pre-ignite or auto-ignite in an engine's combustion chamber.The cylinder head and the engine oil are part of the automobile systems that helps in fuel combustion.

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two punds of water vapor at 30 psia fill the 4ft3 left chmaber of a partitioned system. The right chmaber has twice the volume o
tamaranim1 [39]

Answer:

pressure of water will be 49.7 atm

Explanation:

given data

pressure = 30 psi = 2.04 atm

water = 2 pound = 907.18

mole of water vapor = 907.19 /2 = 50.4 mole

volume = 4 ft³ = 113.2 L

temperature = 40 F = 277.59 K

to find out

pressure of water

solution

we will apply here ideal gas condition

that is

PV = nRT  .......................1

put here all value and here R = 0.0821 , T temperature and V volume and P pressure and n is no of mole

and we get here temperature

PV = nRT  

2.04 × 113.2 = 50.4×0.0821×T

solve it and we get

T = 55.8 K

so we have given right chamber has twice the volume of the left chamber i.e

volume = twice of volume + volume

volume = 2(113.2) + 113.2

volume = 339.6 L

so from equation 1 pressure will be

PV = nRT

P(339.6) = 50.4 × ( 0.0821) × (277.59)

P = 3.3822 atm = 49.7 atm

so pressure of water will be 49.7 atm

7 0
3 years ago
Name some devices we use to make measurements
NikAS [45]

Answer:

Explanation:

Ruler. A steel ruler aids the measurement and layout of straight lines. The ruler, also called "straightedge" or "straight-edged ruler," is a long, thin strip of wood, metal or plastic marked with increments of measurement.

Measuring Tape. The modern measuring tape's roughly palm-sized casing contains a coiled strip of metal marked with increments of measurement. The metal strip, called "tape," attaches to a spring which automatically retracts the tape into the casing following use.

Walking Tape Measure. The walking tape measure, also called "surveyor's measure," records the distance traveled by a wheel. An operator pushes the measure's wheel, similar to a bicycle wheel, by a handle as an attached ticker box displays feet or meters in the same format as a car's odometer.

Laser Measure. The laser measure offers point and shoot distance measurement. In its most basic form, a laser measure is a hand-held electronic device with a digital display.

4 0
2 years ago
Which has more momentum, a 2.0 kg dog at 41 m/s or a 75 kg pony at 1.0 m/s?
Nesterboy [21]

Answer:

The dog has more momentum than the pony.

Explanation:

To solve this problem, we must remember the formula for calculating momentum, which is given below:

momentum = p = m*v

where m represents the mass of the object and v represents the velocity of the object

Using this knowledge, let's calculate the momentum for the dog and the pony.

Dog: p = m*v = (2kg)*(41 m/s) = 82 kg*m/s

Pony: p = m*v = (75kg)*(1 m/s) = 75 kg*m/s

Since 82 > 75, we can conclude that the dog has more momentum.

Hope this helps!

3 0
3 years ago
Which statement accurately describes the illustration?
kvv77 [185]
The answer is B. I hope this helps! :)
3 0
3 years ago
Read 2 more answers
When an excited electron falls from n = 3 to n = 2, a red radiation in the Balmer series emitted. What is the frequency of this
vichka [17]

Answer:

The frequency of this photon is 4.57\times10^{14}\ Hz

(D) is correct option.

Explanation:

Given that,

Excited states,

n=3

n=2

We need to calculate the wavelength

Using formula for energy

E=13.6(\dfrac{1}{n^2}-\dfrac{1}{m^2})

E=13.6(\dfrac{1}{4}-\dfrac{1}{9})

E=1.888\ eV

E=1.888\times1.6\times10^{-19}\ J

E=3.0208\times10^{-19}\ J

We need to calculate the frequency

Using formula of frequency

E=hf

f=\dfrac{E}{h}

Where, E =energy

f=\dfrac{3.0208\times10^{-19}}{6.63\times10^{-34}}

f=4.57\times10^{14}\ Hz

Hence, The frequency of this photon is 4.57\times10^{14}\ Hz

4 0
2 years ago
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