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ki77a [65]
3 years ago
5

high school physics, no need detail explain, just give the answer, but you have to make sure thank you

Physics
1 answer:
Goshia [24]3 years ago
6 0

Answer:many questions add point

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A transverse wave on a string has an amplitude a. A tiny spot on the string is colored red. As one cycle of the wave passes by
aliya0001 [1]

Answer:

Option D) 4A

Explanation:

As the cycle of the wave passes by, the amplitude gives the longest journey when the spot travels from the undistributed position. During each cycle the spot travels "Four times" .

Considering one of this cycle, if it begins to travel from it's undistributed position , there would be four movements i.e

* Upward movement through distance A

*Downward movement through distance A

*Downward again through distance A

*Upward through distance A.

Then it would travel back to its undistributed position held

4 0
3 years ago
A baseball is batted from a height of 1.09 m with a speed of
kobusy [5.1K]

(a) The horizontal and vertical components of the ball’s initial velocity is 37.8 m/s and 12.14 m/s respectively.

(b) The maximum height above the ground reached by the ball is 8.6 m.

(c) The distance off course the ball would be carried is 0.38 m.

(d) The ball's velocity after 2.0 seconds if there is no crosswind is 38.53 m/s.

<h3>Horizontal and vertical components of the ball's velocity</h3>

Vx = Vcosθ

Vx = 39.7 x cos(17.8)

Vx = 37.8 m/s

Vy = Vsin(θ)

Vy = 39.7 x sin(17.8)

Vy = 12.14 m/s

<h3>Maximum height reached by the ball</h3>

H = \frac{v^2 sin^2(\theta)}{2g} \\\\H = \frac{(39.7)^2 \times (sin17.8)^2}{2(9.8)} \\\\H = 7.51 \ m

Maximum height above ground = 7.51 + 1.09 = 8.6 m

<h3>Distance off course after 2 second </h3>

Upward speed of the ball after 2 seconds, V = V₀y - gt

Vy = 12.14 - (2x 9.8)

Vy = - 7.46 m/s

Horizontal velocity will be constant = 37.8 m/s

Resultant speed of the ball after 2 seconds = √(Vy² + Vx²)

V = \sqrt{(-7.46)^2 + (37.8)^2} \\\\V = 38.53 \ m/s

<h3>Resultant speed of the ball and crosswind</h3>

V = \sqrt{38.52^2 + 4^2} \\\\V = 38.72 \ m/s

<h3>Distance off course the ball would be carried</h3>

d = Δvt = (38.72 - 38.53) x 2

d = 0.38 m

The ball's velocity after 2.0 seconds if there is no crosswind is 38.53 m/s.

Learn more about projectiles here: brainly.com/question/11049671

5 0
1 year ago
Which energy transformations BEST illustrates why people can walk? A) Chemical energy is being converted into light energy. B) C
Gekata [30.6K]

The answer is letter c.

The explanation behind this is when human consumes a plant or when a human being eats an animal that ate a plant. The chemical energy kept in the plant (or animal) cells is progressed into the cells of the human's body. All of the body progressions, like ingestion, breathing, pumping blood, are driven by cells changing the kept chemical energy into heat and work, in a procedure called respiration. In the muscle cells of the human (or any animal), the chemical energy is converted into mechanical work and heat. The muscle pacts, the legs thrust, and the body jumps into the air. 

5 0
3 years ago
Read 2 more answers
Imagine that you pushed a box, applying a force of 30 Newton’s , over a distance of 5 meters. How much would you do have done ?
kati45 [8]
30 ),which is the force,divided by 5
30÷5=6
7 0
3 years ago
Read 2 more answers
A 6.9 kg object is suspended by a string from the ceiling of an elevator. The acceleration of gravity is 9.8 m/s 2 . Determine t
lina2011 [118]

Answer:

Tension, T = 87.63  N

Explanation:

Given that,

Mass of the object, m = 6.9 kg

The string is acting in the upward direction, a = 2.9 m/s²

Acceleration due to gravity, g = 9.8 m/s²

As the lift is accelerating upwards, it means the net force acting on it is given by :

T = m(a+g)

= 6.9 (2.9+9.8)

= 6.9(2.7)

= 87.63  N

So, the tension in the string is 87.63  N.

6 0
3 years ago
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