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Stolb23 [73]
2 years ago
5

characterizing vibration-assisted atomic force microscopy (afm)-based nanomachining via perception of acoustic emission phenomen

a using a sensor-based real-time monitoring approach
Physics
1 answer:
DaniilM [7]2 years ago
8 0

The study 'characterizing vibration-assisted atomic force based nanomachining' aims to elucidate nanomachine properties for heterogeneous materials.

<h3>What is nanomachining?</h3>

The expression nanomachining makes reference to the study of nanometric machines (nanomachines) and related materials, which can be achieved by different approaches including sensor-based strategies related to acoustic auditive phenomena.

In conclusion, the study 'characterizing vibration-assisted atomic force based nanomachining' aims to elucidate nanomachine properties for heterogeneous materials.

Learn more about nanomachines here:

brainly.com/question/20875598

#SPJ1

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A person pushes a block 4 m with a force of 25 N. How much work is being done?
Elina [12.6K]

Answer:

<h2>100 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 25 × 4

We have the final answer as

<h3>100 J</h3>

Hope this helps you

3 0
3 years ago
Arm abcd is pinned at b and undergoes reciprocating motion such that θ=(0.3 sin 4t) rad, where t is measured in seconds and the
storchak [24]
<span>θ=0.3sin(4t)
w=0.3cost(4t)(4)=1.2cost(4t)
a=-4.8sin(4t)

cos4t max will always be 1 (refer to cos graph), for same reason, sin4t will always be 0

therefore, wmax=1.2rad/s
 
vAmax=r*w=250*1.2=300mm/s
(may be different if your picture/radius is from a different picture)

adt=a*r=200*-4.8sin(4t)=0 (sin(4t)=0)

adn=r*w^2=200*1.2^2=288

ad= square root of adt^2+adn^2 = 288mm/s^2</span>
8 0
3 years ago
A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of mc001-1. Jpg 6. 67
Andrei [34K]

The approximate length of the arc intersected by the central angle is 20.94 inches.

The given parameters:

  • <em>Radius of the circle, r = 10 inches</em>
  • <em>Central angle, </em>\theta = \frac{2\pi }{3} \ rad<em />

<em />

The approximate length of the arc intersected by the central angle is calculated as follows;

S = rθ

where;

  • <em>S is the length of the arc</em>

Substitute the given parameters and solve for the length of the arc

S = 10 \ in \times \frac{2\pi }{3} \\\\S = 20.94 \ inches

Thus, the approximate length of the arc intersected by the central angle is 20.94 inches.

<em>Your question is not complete, find the complete question below:</em>

A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of \frac{2\pi}{3}.

Learn more about length of arc here: brainly.com/question/2005046

5 0
3 years ago
A 18-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 30 N. Starting from rest, the sle
k0ka [10]

Answer:

Coefficient of kinetic friction = 0.146

Explanation:

Given:

Mass of sled (m) = 18 kg

Horizontal force (F) = 30 N

FInal speed (v) = 2 m/s

Distance (s) = 8.5 m

Find:

Coefficient of kinetic friction.

Computation:

Initial speed (u) = 0 m/s

v² - u² = 2as

2(8.5)a = 2² - 0²

a = 0.2352 m/s²

Nweton's law of :

F (net) = ma

30N - μf = 18 (0.2352)

30 - 4.2336 = μ(mg)

25.7664 =  μ(18)(9.8)

μ = 0.146

Coefficient of kinetic friction = 0.146

6 0
4 years ago
Pls help it's due today​
mario62 [17]

Answer:

Breh seriously. Ugh fine.

1.B

2.D

3.C

4.C

5.D,A and B

6.A,C and D

3 0
2 years ago
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