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LenaWriter [7]
3 years ago
12

Match each statement with the type of contraceptive it describes

Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

Can I see some answer choices please, then I'll gladly answer it.

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A train travels 55 kilometers in 2 hours, and then 52 kilometers in 5 hours. What is its average speed?
bulgar [2K]

The formula for working out speed is distance ÷ time.

55 km ÷ 2 hours = 27.5 km/h (average speed for first part of journey)

52km ÷ 5 hours = 10.4 km/h (average speed for second part of journey)

(27.5 + 10.4) ÷ 2 = 18.95 km/h (average speed throughout the journey)

4 0
3 years ago
Read 2 more answers
How does food affects carbon footprint?
eduard

Answer:

Food accounts for 10-30% of a household's carbon footprint, typically a higher portion in lower-income households. Production accounts for 68% of food emissions, while transportation accounts for 5%.

Explanation:

6 0
3 years ago
Read 2 more answers
4. A crane has a weight of 85000 N and it rests on two caterpillar tracks which have a total
vagabundo [1.1K]

Answer:

50kPa and if the area decreases, the pressure increases

Explanation:

P=F/A; P=pressure, F=force, A=area

85000N/1.7 m^2 = 50000 N/m^2; Pa = Pascal = N/m^2

=50 kPa

4 0
3 years ago
When an electric current flows through a wire a
Rama09 [41]

Answer:

Option C. is correct

Explanation:

The magnetic field is the area around a magnet in which there is magnetic force. When an electric current flows through a wire a  magnetic field is created. A single wire does not produce a strong magnetic field. So, to increase the power  of the magnetic field, increase the number of coils in the wire.

3 0
3 years ago
In the diagram, q1 = +4.88*10^-8 C.
MAVERICK [17]

Answer:

ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)

Explanation:

The potential difference while moving from point A to Point B is given as follows:

\Delta V = V_B-V_A

where,

ΔV = potential difference from A to B = ?

V_A = Potential at point A = \frac{kq}{r_A}

V_B = Potential at point B = \frac{kq}{r_B}

Therefore,

\Delta V = \frac{kq}{r_B}-\frac{kq}{r_A}\\\\\Delta V = kq(\frac{1}{r_B}-\frac{1}{r_A})

where,

k = Colomb's Constant = 9 x 10⁹ N.m²/C²

q = magnitude of charge = 4.88 x 10⁻⁸ C

r_A = distance of point A from charge = 1.36 m

r_B = distance of point B from charge = 0.538 m

Therefore,

\Delta V = (9\ x\ 10^9\ N.m^2/C^2)(4.88\ x\ 10^{-8}\ C)(\frac{1}{0.538\ m}-\frac{1}{1.36\ m})\\\\\Delta V = (439.2 N.m^2/C)(2.59\ /m)

<u>ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)</u>

7 0
3 years ago
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