Below is an attachment of the Lewis structure with the lowest formal charges.
The formal charge is the fictitious charge that an atom in a molecule would have if the electrons in the bonds were evenly distributed among the atoms. The nonbonding electrons on a neutral atom are subtracted from its valence electron count, which is then followed by the number of bonds that bind it to other atoms in the Lewis structure, to get the formal charge. This is another way to put it. When hyponitrous acid is oxidized in the atmosphere, nitric and nitrous acids are produced. By reducing a nitrate or nitrite by sodium amalgam in the presence of water, hyponitrite salts have been created.
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To completely convert 9. 0 moles of hydrogen gas (h2) to ammonia gas, 3.0 moles of nitrogen gas (n2) are required.
<h3>What are moles?</h3>The mole is a SI unit of measurement that is used to calculate the quantity of any substance.
<h3 />The given reaction is
By the stoichiometry rule of ratio hydrogen: nitrogen
3 : 1
The reacted moles of nitrogen is equals to H/3 moles of reacted hydrogen
So, moles of nitrogen
Thus, 3.0 moles of nitrogen gas (n2) are required.
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Taking into account definition of percent yield, the percent yield for the reaction is 84.88%.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
2 Al + 3 H₂SO₄ → Al₂(SO₄)₃ + 3 H₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
The molar mass of the compounds is:
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
The following rule of three can be applied: if by reaction stoichiometry 54 grams of aluminium form 342 grams of aluminium sulfate, 14 grams of aluminium form how much mass of aluminium sulfate?
<u><em>mass of aluminium sulfate= 88.67 grams</em></u>
Then, 88.67 grams of aluminium sulfate can be produced if 14.0 g of aluminium reacts with excess sulfuric acid.
<h3>Percent yield</h3>The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.
The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:
where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.
<h3>Percent yield for the reaction in this case</h3>In this case, you know:
Replacing in the definition of percent yields:
Solving:
<u><em>percent yield= 84.88%</em></u>
Finally, the percent yield for the reaction is 84.88%.
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the reaction stoichiometry:
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