M.P of oleic acid = 13 deg C
<span>B.Pof oleic acid = 360 deg C </span>
<span>(360 - 13) / 100 = 3.47 </span>
<span>So 1 deg O = 3.47 deg C </span>
<span>The scale do not start at 0 deg C, it starts at 13 deg C. So to convert deg C to deg O,
subtract 13 then divide by 3.47 </span>
<span>deg O = (deg C - 13) / 3.47 </span>
<span>convert O to C multiply by 3.47 then add 13 </span>
<span>deg C = (deg O x 3.47) + 13 </span>
<span>convert 0 deg C to deg O </span>
<span>deg O = (0 deg C - 13) / 3.47 </span>
<span>= - 3.75 deg O</span>
Answer:
Solution given:
c) Magnesium metal plus silver acetate (teachers note:
<u>Balanced</u><u> </u><u>chemical</u><u> </u><u>equation</u><u>:</u>

d) hydrobromic acid plus zinc metal (teachers note:
<u>Balanced chemical equation:</u>

<span>Volume = 2.00 L
Molarity = 0.500 M
M = n / V
0.500 = n / 2.00
n = 0.500 * 2.00
n = 1.0 mole KNO</span>₃<span>
Molar mass KNO</span>₃ = <span>101.1032 g/mol
</span>
1 mole ------ <span>101.1032 g
</span>1.0 mole ------ ?
mass = 1.0 * 101.1032 g / 1
mass = 101.1032 g of KNO₃
hope this helps!
No because the limiting reactant is determined by calculating the amount of product therefore the limiting reactant will not be the same for a given reaction