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3 years ago

2 N2 (g) + O2 (g) ---> 2 N2O (g) H= +163.2 kj/mol

Chemistry

1 answer:

VLD [36.1K]3 years ago

5 0

Answer:

46.3 kJ

Explanation:

Step 1: Write the thermochemical equation

2 N₂(g) + O₂(g) ⇒ 2 N₂O(g) ΔH= +163.2 kJ/mol

Step 2: Calculate the moles corresponding to 25.0 g of N₂O

The molar mass of N₂O is 44.01 g/mol.

25.0 g × (1 mol/44.01 g) = 0.568 mol

Step 3: Calculate the heat released when 0.568 moles of N₂O are produced

According to the thermochemical equation, 163.2 kJ are required per 2 moles of N₂O.

0.568 mol × (163.2 kJ/2 mol) = 46.3 kJ

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3 years ago

What further observation led mendeleev to create the periodic table

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Answer:

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Explanation:

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3 years ago

Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.30 MJ o

Sunny_sXe [5.5K]

Answer:

97 000 g Na

Explanation:

The absortion (or liberation) of energy in form of heat is expressed by:

q=m*Cp*ΔT

The information we have:

q=1.30MJ= 1.30*10^6 J

ΔT = 10.0°C = 10.0 K (ΔT is the same in °C than in K)

Cp=30.8 J/(K mol Na)

If you notice, the Cp in the question is in relation with mol of Na. Before using the q equation, we can find the Cp in relation to the grams of Na.

To do so, we use the molar mass of Na= 22.99g/mol

$Cp= \frac{30.8J}{K*mol Na}*\frac{1 mol Na}{22.99 g Na}=1.34\frac{J}{K*g Na}$

Now, we are able to solve for m:

$m=\frac{1.30*10^6 J}{1.34\frac{J}{K*g Na} *10.0K}=\frac{1.30*10^6J}{13.4\frac{J}{g Na} } = 9.70*10^4 g Na=97 Kg Na$ =97 000 g Na

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3 years ago

Read 2 more answers

Please help! BRAINLIEST to right answer

Anastasy [175]

Answer:

Hailey the answer is D.

Explanation:

if liquid to solid is exothermic then then the other way around would be endorhermic

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3 years ago

How many moles are in 9.50 x 1022 molecules of CO? Be sure to ALL work below and report your answer using the correct number of

eimsori [14]

Answer:

0.158 moles

Explanation:

We are given;

9.50 x 10^22 molecules of CO

We are required to determine the number of moles;

We need to know;

1 mole of a compound = 6.022 × 10^23 molecules

Therefore;

9.50 x 10^22 molecules of CO will be equivalent to;

= 9.50 x 10^22 molecules ÷ 6.022 × 10^23 molecules/mole

= 0.158 moles

Therefore, the number of moles are 0.158 moles

4 0

3 years ago