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KengaRu [80]
3 years ago
6

Which formulas could represent the empirical formula and the molecular formula of a given compound?

Chemistry
1 answer:
Alina [70]3 years ago
7 0

Answer:

d

Explanation:

d

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Select all of the answers that apply.
katovenus [111]

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Actually Welcome to the Concept of the Geography.

Surface currents in a ocean or a sea are driven by Winds.

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3 years ago
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When 280. mL of 1.50 × 10⁻⁴ M hydrochloric acid is added to 135 mL of 1.75 × 10⁻⁴ M Mg(OH)₂, the resulting solution will be?
goldfiish [28.3K]

Answer:

B is the correct answer!

Explanation:

Balanced equation is Mg(OH)2 + 2 HCl = MgCl2 + 2 H2O

HCl  is the limiting reactant because it gives the smaller amount of  MgCl2 I did the math. This means you will be left with Mg(OH)2 since HCl completely runs out.

If  HCl  is the limiting reactant,  Mg(OH) 2  is the excess reactant.

Mg(OH) 2  is a base, so the solution will be basic.

6 0
3 years ago
You need to make an aqueous solution of 0.215 M aluminum bromide for an experiment in lab, using a 300 mL volumetric flask. How
Karo-lina-s [1.5K]

Answer:

We have to add 17.2 grams of aluminium bromide

Explanation:

Step 1: Data given

Molarity of the aluminum bromide solution = 0.215 M

Volume = 300 mL = 0.300 L

Molar mass aluminium bromide = 266.69 g/mol

Step 2: Calculate moles Aluminium bromide

moles AlBr3 = volume * molarity

Moles AlBr3 = 0.300 L * 0.215 M

Moles AlBR3 = 0.0645 moles

Step 3: Calculate mass aluminium bromide

Mass aluminium bromide = moles AlBr3 * molar mass AlBr3

Mass aluminium bromide = 0.0645 moles * 266.69 g/mol

Mass aluminium bromide = 17.2 grams

We have to add 17.2 grams of aluminium bromide

3 0
3 years ago
A rigid 3.80 L sealed vessel contains 0.650 mol Ne, 0.321 mol Kr, and 0.190 mol Xe. Find the density of the mixture in g/L.
Eddi Din [679]

Answer:

17.09g/L

Explanation:

Density = total mass of elements/ volume

We need to find the mass of each mixture constituents using their molar mass:

mole = mass/molar mass

For Neon (Ne) which contains 0.650mol;

0.650 = mass/20.18

mass = 0.650 × 20.18

mass = 13.12g

For Krypton (Kr) which contains 0.321mol;

0.321 = mass/83.79

mass = 0.321 × 83.79

mass = 26.89g

For Xenon (Xe) which contains 0.190mol;

0.190 = mass/131.3

mass = 0.190 × 131.3

mass = 24.95g

Total mass = 13.12g + 26.89g + 24.95g = 64.96g

Density = total mass / volume

Density = 64.96g / 3.80L

Density of the mixture = 17.09g/L

7 0
3 years ago
HELP!!!!!!! How many moles of AgNO3 must react to form 0.854 mol Ag?<br> mol AgNO3
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There is 0.854 moles in AgNO3
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