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KengaRu [80]
2 years ago
6

Which formulas could represent the empirical formula and the molecular formula of a given compound?

Chemistry
1 answer:
Alina [70]2 years ago
7 0

Answer:

d

Explanation:

d

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A polyatomic ion, also known as a molecular ion, is a charged chemical species (ion) composed of two or more atoms covalently bonded or of a metal complex that can be considered to be acting as a single unit. The prefix poly- means "many," in Greek, but even ions of two atoms are commonly referred to as polyatomic
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3 years ago
A local am radio station broadcasts at a wavelength of 349m, calculate the energy of the wavelength at which it is broadcasting?
Juli2301 [7.4K]

Answer:

E = 5.69x10⁻²⁸m

Explanation:

To solve this question we neeed to convert the wavelength in meters to energy in joules using the equation:

E = hc / λ

<em>Where E is energy in joules, h is Planck's constant = 6.626x10⁻³⁴Js</em>

<em>c is light constant = 3.0x10⁸m/s</em>

<em>And λ is wavelength in meters = 349m</em>

Replacing:

E = 6.626x10⁻³⁴Js*3.0x10⁸m/s / 349m

E = 5.69x10⁻²⁸m

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3 years ago
What is corona virus explain plss
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3 years ago
Read 2 more answers
What mass of barium sulfate (233 g/mol) is produced when 125 mL of a 0.150 M solution of barium chloride is mixed with 125 mL of
Rzqust [24]

Answer:

4.37 g of barium sulphate

Explanation:

The reaction equation is;

3BaCl2(aq) + Fe2(SO4)3(aq) ---->3 BaSO4(s) + 2FeCl3(aq)

From the question, the number of moles of both barium chloride and FeSO4 = 125/1000 L × 0.150 M = 0.01875 moles

To find the limiting reactant;

3 moles of barium chloride yields 3 moles of barium sulphate

0.01875 moles of barium chloride yields 3 × 0.01875 moles/3 = 0.01875 moles of barium sulphate

1 mole of iron III sulphate yields 3 moles of barium sulphate

0.01875 molesof iron III sulphate yields 0.01875 moles ×3/1 = 0.05625 moles of barium sulphate

Hence,barium chloride is the limiting reactant

Amount of barium sulphate produced = 0.01875 moles × 233 g/mol = 4.37 g of barium sulphate

4 0
2 years ago
1. What is the molarity of a solution prepared by dissolving 3.11 grams of NaOH in
Elena L [17]

The molarity of a solution prepared by dissolving 3.11 grams of NaOH in

enough water to make 300 milliliters of solution is 0. 256 mol/ L

Explanation:

<h3>What is Molarity?</h3>

Molarity (M) is the amount of a substance in a given volume of solution. It is otherwise known as the number of moles of solute in a certain amount of solution.

The unit of molarity is mol/L

<h3>Formula for calculating molarity :</h3>

Molarity = number of moles of solute divided by the volume of the solution\

<h3>Parameters </h3>

Molarity = ?

Number of  moles is calculated using :

Mass of the solute = 3.11 grams of NaOH

Molar mass of the solute = Na + O + H

Let's input the atomic numbers of the elements: Na (23) , O (16) , H (1)

Molar mass of NaOH = 23 + 16 + 1 = 40 g/ mol

Number of moles = 3.11 ÷ 40 = 0.077 mol

Volume of the solution is measured in Liters

Let's convert 300 milliters to liters = 300 divided by 1000 = 0.3 Liters

Molarity = 0.077 ÷ 0.3 = 0. 256 mol/ L

Therefore, the Molarity of the solution is 0. 256 mol/ L

Read more on molarity here :

brainly.com/question/26873446

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2 years ago
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