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KengaRu [80]
3 years ago
6

Which formulas could represent the empirical formula and the molecular formula of a given compound?

Chemistry
1 answer:
Alina [70]3 years ago
7 0

Answer:

d

Explanation:

d

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Calculate the mass of ZnCl2 produced by the reaction of 49.8 grams of H2. Zn + 2HCl ZnCl2 + H2
tester [92]

Answer:

3300.85 g

Explanation:

Given data:

Mass of ZnCl₂ produced = ?

Mass of H₂ produced = 49.8 g

Solution:

Chemical equation:

Zn + 2HCl     →    ZnCl₂ + H₂

Number of moles of  H₂:

Number of moles = mass/molar mass

Number  of moles = 49.8 g/ 2.056 g/mol

Number  of moles = 24.22 mol

Now we will compare the moles of H₂ with ZnCl₂ form balance chemical equation.

                         H₂              :              ZnCl₂

                          1                :                   1

                        24.22         :              24.22

Mass of ZnCl₂:

Mass = number of moles × molar mass

Mass =  24.22 × 136.286 g/mol

Mass = 3300.85 g

6 0
3 years ago
The atomic mass of an element is equal to the:
Stells [14]

Answer:

number of protons and neutrons

Explanation:

4 0
3 years ago
Read 2 more answers
Carbon dioxide in the atmosphere can be reduced by _.*​
pychu [463]

Answer:

As the use of plants as carbon sinks can be undone by events such as wildfires, the long-term reliability of these approaches has been questioned. Carbon dioxide that has been removed from the atmosphere can also be stored in the Earth's crust by injecting it into the subsurface, or in the form of insoluble carbonate salts (mineral sequestration).

HOPE IT HELPS

TAKE CARE

Explanation:

6 0
3 years ago
Read 2 more answers
ANSWER ASAP
Aleksandr-060686 [28]

Answer:

4 orbits in the fourth period.

19 electrons in the atom from group 1 and fourth period.

Explanation:

Potassium has 19 electrons distributed in its 4 orbits

5 0
3 years ago
Combustion analysis of 0.300 g of an unknown compound containing carbon, hydrogen, and oxygen produced 0.5213 g of co2 and 0.283
Lyrx [107]
First, we have to get how many grams of C & H & O in the compound:
- the mass of C on CO2 = mass of CO2*molar mass of C /molar mass of CO2
                                        = 0.5213 * 12 / 44 = 0.142 g
- the mass of H atom on H2O = mass of H2O*molar mass of H / molar mass of H2O
                                                 =0.2835 * 2 / 18 = 0.0315 g
- the mass of O = the total mass - the mass of C atom - the mass of H atom
                          =  0.3 - 0.142 - 0.0315 = 0.1265 g
Convert the mass to mole by divided by molar mass
C(0.142/12) H(0.0315/2) O(0.1265/16) 
C(0.0118) H(0.01575) O(0.0079) by dividing by the smallest value 0.0079
C1.504 H3.99 O1 by rounding to the nearst fraction
C3/2 H4/1 )1/1 multiply by 2 
∴ the emprical formula C3H8O2
           



6 0
3 years ago
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