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UkoKoshka [18]
3 years ago
8

A rare form of a mineral that is usually very clear and brightly colored is what?

Chemistry
2 answers:
Ksivusya [100]3 years ago
3 0
Its a gem
hope this helps♥♥♥
Ivahew [28]3 years ago
3 0

Answer:

gem

Explanation:

because, gems are usually brightly colored when it comes to diffrent outer material looks

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Given the balanced equation representing a reaction:
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D Direction of motion I hope this helps
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Why are the outer-most electrons the only ones included in the electron dot<br> diagram?
kupik [55]

Answer:

Atoms with 5 or more valence electrons gain electrons forming a negative ion, or anion. why are outermost electrons only ones included in orbital filling diagram? they are the only ones involved in chemical reactions and bonding. ... 2s orbital is farther from the nucleus meaning it has more energy.

Explanation:

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3 years ago
In a study of the following reaction at 1200 K it was observed that when the equilibrium partial pressure of water vapor is 15.0
sp2606 [1]

Answer:

The value of K_p for this reaction at 1200 K is 4.066.

Explanation:

Partial pressure of water vapor at equilibrium = p^o_{H_2O}=15.0 Torr

Partial pressure of hydrogen gas at equilibrium = p^o_{H_2}=?

Total pressure of the system at equilibrium P = 36.3 Torr

Applying Dalton's law of partial pressure to determine the partial pressure of hydrogen gas at equilibrium:

P=p^o_{H_2O}+p^o_{H_2}

p^o_{H_2}=P-p^o_{H_2O}=36.3 Torr- 15.0 Torr = 21.3 Torr

3 Fe(s) 4 H_2O(g)\rightleftharpoons Fe_3O_4(s) 4 H_2(g)

The expression of K_p is given by:

K_p=\frac{(p^o_{H_2})^4}{(p^o_{H_2O})^4}

K_p=\frac{(21.3 Torr)^4}{(15.0 Torr)^4}=4.066

The value of K_p for this reaction at 1200 K is 4.066.

6 0
3 years ago
How many photons are produced in a laser pulse of 0.364 J at 477 nm?
Luda [366]

Answer:

1.00 × 10¹⁸

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1. Calculate the <em>energy of one photon</em>

The formula for the energy of a photon is

<em>E</em> = <em>hc</em>/λ  

<em>h</em> = 6.626 × 10⁻³⁴ J·s; <em>c</em> = 2.998 × 10⁸ m·s⁻¹

λ = 477 nm = 477 × 10⁻⁹ m                              Insert the values

<em>E</em> = (6.626 × 10⁻³⁴ × 2.998× 10⁸)/(477 × 10⁻⁹)

<em>E</em> = 4.165× 10⁻¹⁹ J

2. Calculate the <em>number of photons</em>

Divide the total energy by the energy of one photon.

No. of photons = 0.418 × 1/4.165 × 10⁻¹⁹      

No. of photons = 1.00 × 10¹⁸

7 0
3 years ago
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