The central iodine atom in triiodide has sp3d hybridization.In triiodide anion, the central iodine atom has three equatorial lone pairs of electrons and the terminal iodines are bonded axially in a linear shape. Electrons in sp3d hybridization are arranged in trigonal bipyramidal symmetry.
Explanation:
When you draw the Lewis structure of this particle, you'll realize that the central I atom has a pair of bonds and three individual pairs of electrons. as a result of there are five things around that central I atom, it's<span> sp3d hybridized.
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The bonds during a gas<span> (CH4) molecule </span>are fashioned<span> by four separate </span>however<span> equivalent orbitals; </span>one<span> 2s and </span>3<span> 2p orbitals of the carbon </span>interbreed<span> into four sp3 orbitals. </span>within the<span> ammonia molecule (NH3), 2s and 2p orbitals </span>produce<span> four sp3hybrid orbitals, </span>one among that<span> is occupied by a lone </span>try<span> of electrons.</span><span>
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Answer:
heterogeneous : A mixture that consists of visibly different substances or phases.
homogeneous : A mixture that has the same uniform appearance and composition throughout its mass.
compound: A pure chemical substance consisting of two or more different chemical elements.
element: A substance consisting one type of atom.
Answer:
0.5 M
Explanation:
From the question given above, the following data were obtained:
Mass of NaOH = 80 g
Volume of solution = 4 L
Molarity =?
Next, we shall determine the number of mole in 80 g of NaOH. This can be obtained as follow:
Mass of NaOH = 80 g
Molar mass of NaOH = 23 + 16 + 1
= 40 g/mol
Mole of NaOH =?
Mole = mass / molar mass
Mole of NaOH = 80 / 40
Mole of NaOH = 2 moles
Finally, we shall determine the molarity of the solution. This can be obtained as follow:
Mole of NaOH = 2 moles
Volume of solution = 4 L
Molarity =?
Molarity = mole / Volume
Molarity = 2/4
Molarity = 0.5 M
Therefore, the molarity of the solution is 0.5 M.